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Re: Cannot step through asynchronous iterator manually

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On 30 January 2016 at 13:45, Frank Millman <frank@chagford.com> wrote:
> "Oscar Benjamin"  wrote in message
> news:CAHVvXxSA0Yq4VOYy6qycgXxVpL5zZGM8muUi+1VmeZD8CRgtvg@mail.gmail.com...
>>
>>
>> The simplest thing would just be to call list(cur) but I realise that
>
> you don't want to consume more than 2 rows from the database so just
> use islice:
>>
>>
>> rows = list(islice(cur, 2))  # pull at most 2 rows
>> if not rows:
>>     # no rows
>> elif len(rows) > 1:
>>     # too many rows
>> row = rows[0]
>>
>
> I like the idea, but I don't think it would work with an asychronous
> iterable.

That was intended as an improvement over the code that you posted for
normal iterators.

> OTOH it should not be difficult to roll your own using the example
> in the itertools docs as a base. Except that the example uses next(it)
> internally, and this thread started with the fact that there is no
> asychronous equivalent, so I might be back to square one.

I haven't used PEP 492 yet but what about:

async def aslice(asynciterator, end):
    if end == 0:
        return []
   items = []
   async for item in asynciterator:
       items.append(item)
       if len(items) == end:
           break
    return items

rows = await aslice(cur, 2)

AFAICT there's no generator-function-style syntax for writing an async
iterator so you'd have to make a class with the appropriate methods if
you wanted to be able to loop over aslice with async for.

--
Oscar

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Re: Cannot step through asynchronous iterator manually Oscar Benjamin <oscar.j.benjamin@gmail.com> - 2016-01-30 14:11 +0000

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