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Groups > comp.lang.python > #76348
| References | <53ED6F6F.2030004@gmail.com> |
|---|---|
| From | Ian Kelly <ian.g.kelly@gmail.com> |
| Date | 2014-08-14 21:37 -0600 |
| Subject | Re: timedelta problem |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.13023.1408073905.18130.python-list@python.org> (permalink) |
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On Thu, Aug 14, 2014 at 8:24 PM, luofeiyu <elearn2014@gmail.com> wrote: > import datetime > t1='Sat, 09 Aug 2014 07:36:46 -0700' > t2='Sat, 09 Aug 2014 07:36:46 +0700' > >>> datetime.datetime.strptime(t1,"%a, %d %b %Y %H:%M:%S %z") > datetime.datetime(2014, 8, 9, 7, 36, 46, tzinfo=datetime.timezone(datetime.timed > elta(-1, 61200))) > >>> datetime.datetime.strptime(t2,"%a, %d %b %Y %H:%M:%S %z") > datetime.datetime(2014, 8, 9, 7, 36, 46, tzinfo=datetime.timezone(datetime.timed > elta(0, 25200))) > > > problem : > > t1 is GMT time 2014 00:36:46 > t2 is GMT time 2014 14:36:46 You have it backwards. t1 is a later time than t2. > datetime.datetime.strptime do not give me the right answer. >>> dt1 - dt2 datetime.timedelta(0, 50400) >>> _.seconds // 3600 14 Looks correct to me.
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Re: timedelta problem Ian Kelly <ian.g.kelly@gmail.com> - 2014-08-14 21:37 -0600
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