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Re: what is the "/" mean in __init__(self, /, *args, **kwargs) ?

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Date Thu, 14 Aug 2014 15:19:51 +0800
From luofeiyu <elearn2014@gmail.com>
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To Tim Chase <python.list@tim.thechases.com>
Subject Re: what is the "/" mean in __init__(self, /, *args, **kwargs) ?
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python3.4



On 8/14/2014 10:12 AM, Tim Chase wrote:
> On 2014-08-14 10:01, luofeiyu wrote:
>>   >>> help(int.__init__)
>> Help on wrapper_descriptor:
>>
>> __init__(self, /, *args, **kwargs)
>>       Initialize self.  See help(type(self)) for accurate signature.
>>
>> what is the "/" mean in __init__(self, /, *args, **kwargs) ?
> Where are you seeing this?
>
>
>
> Python 2.7.3 (default, Mar 13 2014, 11:03:55)
> [GCC 4.7.2] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
>>>> help(int.__init__)
> Help on wrapper_descriptor:
>
> __init__(...)
>      x.__init__(...) initializes x; see help(type(x)) for signature
>>>> ^D
>
> Python 3.2.3 (default, Feb 20 2013, 14:44:27)
> [GCC 4.7.2] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
>>>> help(int.__init__)
> Help on wrapper_descriptor:
>
> __init__(...)
>      x.__init__(...) initializes x; see help(type(x)) for signature
>
>
>
> -tkc
>
>

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Re: what is the "/" mean in __init__(self, /, *args, **kwargs) ? luofeiyu <elearn2014@gmail.com> - 2014-08-14 15:19 +0800

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