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| From | Peter Otten <__peter__@web.de> |
| Newsgroups | comp.lang.python |
| Subject | Re: reshape with xyz ordering |
| Date | Tue, 26 Jul 2016 16:59:03 +0200 |
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| Lines | 32 |
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Heli wrote: > I sort a file with 4 columns (x,y,z, somevalue) and I sort it using > numpy.lexsort. > > ind=np.lexsort((val,z,y,x)) > > myval=val[ind] > > myval is a 1d numpy array sorted by x,then y, then z and finally val. > > how can I reshape correctly myval so that I get a 3d numpy array > maintaining the xyz ordering of the data? > > > my val looks like the following: > > x,y,z, val > 0,0,0,val1 > 0,0,1,val2 > 0,0,2,val3 > ... > > Thanks a lot for your help, I'm not sure I understand the question. Does shape = [max(t) + 1 for t in [x, y, z]] cube = myval.reshape(shape) give what you want?
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reshape with xyz ordering Heli <hemla21@gmail.com> - 2016-07-26 07:10 -0700
Re: reshape with xyz ordering Peter Otten <__peter__@web.de> - 2016-07-26 16:59 +0200
Re: reshape with xyz ordering Nobody <nobody@nowhere.invalid> - 2016-07-26 23:55 +0100
Re: reshape with xyz ordering Heli <hemla21@gmail.com> - 2016-07-27 06:01 -0700
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