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Re: Test for an empty directory that could be very large if it is not empty?

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Virgil Stokes <vs@it.uu.se> writes:

> Suppose I have a directory C:/Test that is either empty or contains
> more than 2000000 files, all with the same extension (e.g. *.txt). How
> can I determine if the directory is empty WITHOUT the generation of a
> list of the file names in it (e.g. using os.listdir('C:/Test')) when
> it is not empty?

  def is_empty_dir(dirpath):
      return next(scandir(dirpath), None) is None

 https://github.com/benhoyt/scandir


 --
 Akira

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Re: Test for an empty directory that could be very large if it is not empty? Akira Li <4kir4.1i@gmail.com> - 2014-08-07 16:19 +0400

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