Re: What happens when you 'break' a generator?

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Date	Tue, 29 Jul 2014 09:17:46 +0200
From	Johannes Schneider <johannes.schneider@galileo-press.de>
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On 29.07.2014 09:18, Frank Millman wrote:

there's not print 'done' statement at the and.


> Here I break the loop -
>
> x = test()
> for j in x:
>      print(j)
>      if j == 2:
>          break
>
> Now the output is -
>
> start
> 0
> 1
> 2
>
> 'done' does not appear, so the generator does not actually terminate. What
> happens to it?
>
> My guess is that normal scoping rules apply. Using my example, the generator
> is referenced by 'x', so when 'x' goes out of scope, the generator is
> garbage collected, even though it never completed.
>
> Is this correct?
>
> Frank Millman
>
>
>


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Re: What happens when you 'break' a generator? Johannes Schneider <johannes.schneider@galileo-press.de> - 2014-07-29 09:17 +0200

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