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| Date | Mon, 24 Sep 2012 19:13:39 -0400 |
| Subject | Re: A little morning puzzle |
| From | Dwight Hutto <dwightdhutto@gmail.com> |
| To | Ian Kelly <ian.g.kelly@gmail.com> |
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Show key headers only | View raw
The posted code produces neither a set nor any keys;
> it prints out the same predetermined non-key value multiple times.
This shows multiple dicts, with the same keys, and shows different
values, and some with the same, and that is, in my opinion what the OP
asked for:
a = {}
a['dict'] = 1
b = {}
b['dict'] = 2
c = {}
c['dict'] = 1
d = {}
d['dict'] = 3
e = {}
e['dict'] = 1
x = [a,b,c,d,e]
count = 0
collection_count = 0
search_variable = 1
for dict_key_search in x:
if dict_key_search['dict'] == search_variable:
print "Match count found: #%i = %i" % (count,search_variable)
collection_count += 1
count += 1
print collection_count
The OP can jump in and tell me to alter the example, if they want to.
--
Best Regards,
David Hutto
CEO: http://www.hitwebdevelopment.com
Back to comp.lang.python | Previous | Next — Previous in thread | Find similar | Unroll thread
Re: A little morning puzzle Peter Otten <__peter__@web.de> - 2012-09-19 14:09 +0200
Re: A little morning puzzle Tobiah <toby@tobiah.org> - 2012-09-20 09:28 -0700
Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-22 23:44 -0400
Re: A little morning puzzle alex23 <wuwei23@gmail.com> - 2012-09-23 20:46 -0700
Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-24 17:22 -0400
RE: A little morning puzzle "Prasad, Ramit" <ramit.prasad@jpmorgan.com> - 2012-09-27 17:58 +0000
Re: A little morning puzzle Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-23 22:51 -0600
Re: A little morning puzzle Ethan Furman <ethan@stoneleaf.us> - 2012-09-24 14:18 -0700
Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-24 18:07 -0400
Re: A little morning puzzle Ian Kelly <ian.g.kelly@gmail.com> - 2012-09-24 17:01 -0600
Re: A little morning puzzle Dwight Hutto <dwightdhutto@gmail.com> - 2012-09-24 19:13 -0400
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