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Groups > comp.lang.python > #9802
| References | <39758958-fc2f-4114-a420-d41ce978e277@r28g2000prb.googlegroups.com> |
|---|---|
| Date | 2011-07-18 23:21 +1000 |
| Subject | Re: open urls in browser |
| From | Chris Angelico <rosuav@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.1217.1310995298.1164.python-list@python.org> (permalink) |
On Mon, Jul 18, 2011 at 10:05 PM, srikanth <srikanth007m@gmail.com> wrote: > Ex: http://www.google.com - Pass/Fail. What do you mean by "Pass" or "Fail"? If you send a URL to a web browser, all you'll find out is whether or not the browser accepted it - it won't tell you if the page is valid. If you want that, you don't need a web browser at all - what you want is a simple URL fetcher, such as urllib/urllib2. http://docs.python.org/library/urllib.html http://docs.python.org/release/3.1.3/library/urllib.request.html ChrisA
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open urls in browser srikanth <srikanth007m@gmail.com> - 2011-07-18 05:05 -0700
Re: open urls in browser Chris Angelico <rosuav@gmail.com> - 2011-07-18 23:21 +1000
Re: open urls in browser srikanth <srikanth007m@gmail.com> - 2011-07-18 06:36 -0700
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