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Groups > comp.lang.python > #74337
| Date | 2014-07-11 11:29 +1000 |
|---|---|
| From | Cameron Simpson <cs@zip.com.au> |
| Subject | Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example |
| References | <981c1f5f-2c19-4efc-8397-796bde07f39b@googlegroups.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.11746.1405042179.18130.python-list@python.org> (permalink) |
On 10Jul2014 08:37, fl <rxjwg98@gmail.com> wrote:
>This example is from the link:
>
>https://wiki.python.org/moin/RegularExpression
>
>I have thought about it quite a while without a clue yet.
>I notice that it uses
>double quote ", in contrast to ' which I see more often until now.
With raw strings (r', r") this doesn't matter. I tend to use r' myself.
You want raw strings with regular expressions because otherwise their heavy use
of sloshes "\" overlap with Python's use of sloshes, making everything harder.
>It looks very complicated to me. Could you simplified it to a simple example?
>
>import re
>split_up = re.split(r"(\(\([^)]+\)\))",
> "This is a ((test)) of the ((emergency broadcasting station.))")
>
>...which produces:
>
>["This is a ", "((test))", " of the ", "((emergency broadcasting station.))" ]
Rip off the python punctuation and get the regexp itself:
(\(\([^)]+\)\))
then start from the inside out:
[^)] Any character except a closing bracket.
+ One or more of the preceeding.
Therefore:
[^)]+ One or more characters which are not closing brackets.
Also phrased: at least one character which is not a closing bracket.
Outside this are \( and \): these are literal opening and closing bracket
characters. So:
\(\([^)]+\)\)
Two opening brackets, then at least one character which is not a
closing bracket, then two closing brackets.
The outermost ( and ) are regexp grouping brackets, not text. On their own you
don't need them, but they mark out the regexp between them for later reference
or for use with a repeating modifier like ?, * or +. So in this instance they
do not add anything special to the regexp.
Given the above inside-to-out explaination, does that explain the re.split
result for you?
Cheers,
Cameron Simpson <cs@zip.com.au>
I thought the DoD was a bunch of licensed squids. The last thing you
need is a bunch of unregulated, amateur squids running loose.
- David Wood <davewood@teleport.com>
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How to decipher :re.split(r"(\(\([^)]+\)\))" in the example fl <rxjwg98@gmail.com> - 2014-07-10 08:37 -0700
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Peter Otten <__peter__@web.de> - 2014-07-10 18:49 +0200
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example MRAB <python@mrabarnett.plus.com> - 2014-07-10 18:01 +0100
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Joel Goldstick <joel.goldstick@gmail.com> - 2014-07-10 13:05 -0400
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Albert-Jan Roskam <fomcl@yahoo.com> - 2014-07-10 12:15 -0700
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Cameron Simpson <cs@zip.com.au> - 2014-07-11 11:29 +1000
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Roy Smith <roy@panix.com> - 2014-07-10 22:18 -0400
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Tim Chase <python.list@tim.thechases.com> - 2014-07-10 21:37 -0500
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Roy Smith <roy@panix.com> - 2014-07-10 23:33 -0400
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Chris Angelico <rosuav@gmail.com> - 2014-07-11 14:31 +1000
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example alister <alister.nospam.ware@ntlworld.com> - 2014-07-11 08:00 +0000
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Steven D'Aprano <steve@pearwood.info> - 2014-07-11 09:04 +0000
Re: How to decipher :re.split(r"(\(\([^)]+\)\))" in the example Albert-Jan Roskam <fomcl@yahoo.com> - 2014-07-11 08:18 -0700
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