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| References | <CAHXoDSAFHbPcU+gwvJPsairQMJmFEf1B6Sn2gw3_OHT1_EPw8A@mail.gmail.com> <lopcr6$22a$1@ger.gmane.org> |
|---|---|
| Subject | Re: Newbie coding question - format error |
| From | Martin S <shieldfire@gmail.com> |
| Date | 2014-06-29 20:02 +0200 |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.11329.1404064987.18130.python-list@python.org> (permalink) |
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Thanks for the input. The main thing was that
On 29 Jun 2014, Terry Reedy <tjreedy@udel.edu> wrote:
>On 6/29/2014 3:06 AM, Martin S wrote:
>
>A couple of additional notes:
>
>> x=int(input('Enter an integer '))
>> y=int(input('Enter another integer '))
>> z=int(input('Enter a third integer '))
>> formatStr='Integer {0}, {1}, {2}, and the sum is {3}.'
>
>When the replacement fields and arguments are in the same order, the
>indexes are optional. The following works, and might be less confusing.
>
>formatStr = 'Integer {}, {}, {}, and the sum is {}.'
>
>> equations=formatStr.format(x,y,z,x+y+z)
>
>We no longer have a space shortage ;-). The following is easier to
>read.
>
>equations = formatStr.format(x, y, z, x+y+z)
>
>> print(equations)
>
>Compute quotient and remainder with the divmod function.
>
>q, r = divmod(x, y)
>
>Both are computed at once and x // y and x % y just toss the other
>answer. x // y == divmod(x, y)[0], x % y == divmod(x, y)[1]
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Re: Newbie coding question - format error Martin S <shieldfire@gmail.com> - 2014-06-29 20:02 +0200
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