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| References | <602B90F0-E7FE-4887-ADA1-981FD4179EC7@gmail.com> <CAPTjJmq8w55crQc4zh_=aEF54POryudsr-0WLkMf_AU5-L-ByA@mail.gmail.com> <510F7020-C682-4A4B-B3ED-5D289D17C5DE@gmail.com> |
|---|---|
| Date | 2014-06-08 10:37 +1000 |
| Subject | Re: How to use imported function to get current globals |
| From | Chris Angelico <rosuav@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.10870.1402187886.18130.python-list@python.org> (permalink) |
On Sun, Jun 8, 2014 at 10:28 AM, 1989lzhh <1989lzhh@gmail.com> wrote: > > > 发自我的 iPhone > >> 在 Jun 8, 2014,4:52,Chris Angelico <rosuav@gmail.com> 写道: >> >>> On Sun, Jun 8, 2014 at 3:40 AM, 1989lzhh <1989lzhh@gmail.com> wrote: >>> Here is the code >>> m1.py >>> def f(): >>> print globals() >>> >>> m2.py >>> from m1 import f >>> f()# how to get current module's globals? >> >> As Ian said, you almost certainly do not want to do this. But if you >> have a solid use-case that involves finding the caller's globals, you >> can do it (in CPython - no idea about other Pythons) with the >> backtrace. > Could you give an example ? I do want to get the caller's globals, so I can expose something into current module implicitly. Thanks! Frankly, no. I don't want to encourage implicitly exposing something like that! Why do you want that, rather than something explicit and clear? ChrisA
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Re: How to use imported function to get current globals Chris Angelico <rosuav@gmail.com> - 2014-06-08 10:37 +1000
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