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Groups > comp.lang.python > #72044
| From | Ned Batchelder <ned@nedbatchelder.com> |
|---|---|
| Subject | Re: Loop thru the dictionary with tuples |
| Date | 2014-05-25 22:13 -0400 |
| References | <CA+FnnTwpQKTyvROYq32YsDfwDooDXRbRg-SYGGhFs1T1D9o_Ow@mail.gmail.com> <llsstb$1sa$1@ger.gmane.org> <llu7ni$dph$1@ger.gmane.org> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.10326.1401070507.18130.python-list@python.org> (permalink) |
On 5/25/14 10:09 PM, Dave Angel wrote: > Ned Batchelder <ned@nedbatchelder.com> Wrote in message: >> On 5/25/14 8:55 AM, Igor Korot wrote: >>> Hi, ALL, >>> I have a following data structure: >>> >>> my_dict[(var1,var2,var3)] = None >>> my_dict[(var4,var5,var6)] = 'abc' >>> >>> What I'm trying to do is this: >>> >>> for (key,value) in my_dict: >>> #Do some stuff >>> >>> but I'm getting an error "Too many values to unpack". >>> >>> What am I doing wrong? >>> >>> Thank you. >>> >> >> You want: >> >> for key, value in my_dict.items(): # or .iteritems() >> >> Iterating over a dictionary gives you its keys. items() will give you >> key,value pairs. > > > Or, if the dict is large, you might want > > for key in my_dict: > value = my_dict [key] > ... For a large dict, .iteritems (Python 2) or .items (Python 3) are perfectly fine and don't have a cost to avoid. .items (Python 2) produces a list, which would be bad. -- Ned Batchelder, http://nedbatchelder.com
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Re: Loop thru the dictionary with tuples Ned Batchelder <ned@nedbatchelder.com> - 2014-05-25 22:13 -0400
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