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Groups > comp.lang.python > #68476
| From | John Gordon <gordon@panix.com> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: Ordering in the printout of a dictionary |
| Date | 2014-03-18 02:56 +0000 |
| Organization | PANIX Public Access Internet and UNIX, NYC |
| Message-ID | <lg8ckl$aro$1@reader1.panix.com> (permalink) |
| References | <lg8462$fnk$1@news.albasani.net> <mailman.8231.1395103693.18130.python-list@python.org> |
In <mailman.8231.1395103693.18130.python-list@python.org> Chris Angelico <rosuav@gmail.com> writes:
> > Is there a way to force a certain ordering of the printout or else
> > somehow manage to get at least a certain stable ordering of the
> > printout (i.e. input and output are identical)?
> Yes; instead of simply printing it out (which calls repr()),
> explicitly iterate over it, like this:
> def display(d):
> return '{'+','.join('%r: %r'%(key,d[key]) for key in sorted(d))+'}'
You could also use the OrderedDict type, which is subclass of dict that
preserves insertion order.
--
John Gordon Imagine what it must be like for a real medical doctor to
gordon@panix.com watch 'House', or a real serial killer to watch 'Dexter'.
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Ordering in the printout of a dictionary Mok-Kong Shen <mok-kong.shen@t-online.de> - 2014-03-18 01:32 +0100
Re: Ordering in the printout of a dictionary Chris Angelico <rosuav@gmail.com> - 2014-03-18 11:48 +1100
Re: Ordering in the printout of a dictionary John Gordon <gordon@panix.com> - 2014-03-18 02:56 +0000
Re: Ordering in the printout of a dictionary Marc Christiansen <usenetmail@solar-empire.de> - 2014-03-18 08:36 +0100
Re: Ordering in the printout of a dictionary Chris Angelico <rosuav@gmail.com> - 2014-03-18 18:55 +1100
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