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Re: Getting globals of the caller, not the defining module

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On 11/11/2013 12:02, sg552@hotmail.co.uk wrote:
> (Sorry for posting through GG, I'm at work.)
>
> On Monday, November 11, 2013 11:25:42 AM UTC, Steven D'Aprano wrote:
>> Suppose I have a function that needs access to globals:
>>
>> # module A.py
>> def spam():
>>      g = globals()  # this gets globals from A
>>      introspect(g)
>>
>> As written, spam() only sees its own globals, i.e. those of the module in
>> which spam is defined. But I want spam to see the globals of the caller.
>>
>> # module B
>> import A
>> A.spam()  # I want spam to see globals from B
>>
>> I can have the caller explicitly pass the globals itself:
>>
>> def spam(globs=None):
>>      if globs is None:
>>          globs = globals()
>>      introspect(globs)
>>
>> But since spam is supposed to introspect as much information as possible,
>> I don't really want to do that. What (if anything) are my other options?
>
> How about this?
>
> # module A.py
> import inspect
> def spam():
>      return inspect.stack()[1][0].f_globals

Bump. Did this do what you wanted, or not?

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Getting globals of the caller, not the defining module Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-11-11 11:25 +0000
  Re: Getting globals of the caller, not the defining module Chris Angelico <rosuav@gmail.com> - 2013-11-11 22:34 +1100
  Re: Getting globals of the caller, not the defining module sg552@hotmail.co.uk - 2013-11-11 04:02 -0800
    Re: Getting globals of the caller, not the defining module Terry Reedy <tjreedy@udel.edu> - 2013-11-11 20:57 -0500
      Re: Getting globals of the caller, not the defining module Rotwang <sg552@hotmail.co.uk> - 2013-11-12 08:29 +0000
    Re: Getting globals of the caller, not the defining module Rotwang <sg552@hotmail.co.uk> - 2013-11-14 20:56 +0000
      Re: Getting globals of the caller, not the defining module Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2013-11-15 08:23 +0000

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