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Groups > comp.lang.python > #46724
| From | Mok-Kong Shen <mok-kong.shen@t-online.de> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: Output from to_bytes |
| Date | 2013-06-02 21:09 +0200 |
| Organization | albasani.net |
| Message-ID | <kog58p$nmi$1@news.albasani.net> (permalink) |
| References | <knstkh$74a$1@news.albasani.net> <ko2irn$9oh$1@reader1.panix.com> |
Am 28.05.2013 17:35, schrieb Grant Edwards: > On 2013-05-26, Mok-Kong Shen <mok-kong.shen@t-online.de> wrote: >> I don't understand why with the code: >> >> for k in range(8,12,1): >> print(k.to_bytes(2,byteorder='big')) >> >> one gets the following output: >> >> b'\x00\x08' >> b'\x00\t' >> b'\x00\n' >> b'\x00\x0b' >> >> I mean the 2nd and 3rd should be b'\x00\x09' and b'x00\x0a'. >> Anyway, how could I get the output in the forms I want? > > Well, it would help if you told us what output form you want. As I stated, I like the 2nd and 3rd be b'\x00\x09' and b'\x00\x0a' respectively. This is what would expeacted to be in a hexadecimal notation IMHO in other PLs. M. K. Shen
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Output from to_bytes Mok-Kong Shen <mok-kong.shen@t-online.de> - 2013-05-26 14:02 +0200
Re: Output from to_bytes Chris Angelico <rosuav@gmail.com> - 2013-05-26 23:26 +1000
Re: Output from to_bytes Terry Jan Reedy <tjreedy@udel.edu> - 2013-05-26 16:45 -0400
Re: Output from to_bytes Grant Edwards <invalid@invalid.invalid> - 2013-05-28 15:35 +0000
Re: Output from to_bytes Mok-Kong Shen <mok-kong.shen@t-online.de> - 2013-06-02 21:09 +0200
Re: Output from to_bytes Ned Batchelder <ned@nedbatchelder.com> - 2013-06-02 18:18 -0400
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