python program without stackless.run()

Newsgroups	comp.lang.python
Date	2015-06-18 12:47 -0700
Message-ID	<fc770e8e-a269-4325-b211-efe09327c3ea@googlegroups.com> (permalink)
Subject	python program without stackless.run()
From	ravi <temp.sha@gmail.com>

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Hi,

I could not understand how the below program executes function "fun" without calling stackless.run() in the program?  Here "fun" runs as a tasklet and as per my knowledge for that stackless.run() is must.



-----------------------------------------------------------------
import stackless

class A:
    def __init__(self,name):
        self.name = name
        self.ch = stackless.channel()
        stackless.tasklet(self.fun)()

    def __call__(self,val):
        self.ch.send(val)

    def fun(self):
       while 1:
         v = self.ch.receive()
         print "hi" , v


if __name__ == "__main__":
    obj = A("sh")
    obj(6)
-----------------------------------------------------------------

output:
----------
hi 6





thanks,
ravi

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python program without stackless.run() ravi <temp.sha@gmail.com> - 2015-06-18 12:47 -0700
  Re: python program without stackless.run() Ian Kelly <ian.g.kelly@gmail.com> - 2015-06-18 14:10 -0600
    Re: python program without stackless.run() ravi <temp.sha@gmail.com> - 2015-06-18 14:00 -0700

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