Re: Issue with continous incrementing of unbroken sequence for a entire working day

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Date	Thu, 28 Feb 2013 13:07:04 -0800 (PST)
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Subject	Re: Issue with continous incrementing of unbroken sequence for a entire working day
From	Rick Johnson <rantingrickjohnson@gmail.com>
Cc	matt.walker.jones@gmail.com
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On Thursday, February 28, 2013 2:41:30 PM UTC-6, Morten Engvoldsen wrote:
>
> [...]
>
> def salesrecord():
>     serial_number = 0
>     sales_recrod = {'record1':'product1',
>                     'record2':'product2',
>                     'record3':'product3',
>                     }
> 
>     for i in sales_recrod:
>         print sales_recrod[i]
>         serial_number += 1
>     print serial_number
>     fo = open("workfile.txt", "wb")
>     fo.write(str(serial_number))
>     fo.close()
> 
>     with open("workfile.txt", 'r') as f:
>         serial_number = f.read()
>     today = date.today()


I would highly suggest breaking this code into a few specific functions:

def main()
def readDataFile()
def writeDataFile()
def computeDates()
def processSalesRecord()

and then run main from this:

if __name__ == '__main__':
    main()

PS: Please trim superfluous quotes.

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Fwd: Issue with continous incrementing of unbroken sequence for a entire working day Morten Engvoldsen <mortenengv@gmail.com> - 2013-02-28 21:41 +0100
  Re: Issue with continous incrementing of unbroken sequence for a entire working day Rick Johnson <rantingrickjohnson@gmail.com> - 2013-02-28 13:07 -0800

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