Re: Proper conversion of timestamp

From	Gregory Ewing <greg.ewing@canterbury.ac.nz>
Newsgroups	comp.lang.python
Subject	Re: Proper conversion of timestamp
Date	2014-03-05 17:06 +1300
Message-ID	<bnnm6oFgcj1U1@mid.individual.net> (permalink)
References	<CA+FnnTy2zoJYzx+ExkHf8SsENppBLaQzp2zOC9WFYsLBYwK9Qg@mail.gmail.com> <lf5hes$ve3$1@ger.gmane.org> <mailman.7750.1393970120.18130.python-list@python.org>

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Igor Korot wrote:
> What I have is a timestamp which reads: 1289410678L.
> 
> Trying to convert this into the datetime object in Python using:
> 
> import datetime
> datetime.datetime.fromtimestamp( stamp )
> 
> produces the error: timestamp out of range for platform 
> localtime()/gmtime() function.

Divide the timestamp by 1000.0 to give floating point
seconds, and then use datetime.fromtimestamp().

 >>> d = datetime.datetime.fromtimestamp(1289410678 / 1000.0)
 >>> d
datetime.datetime(1970, 1, 16, 10, 10, 10, 678000)
 >>> d.strftime("%Y-%m-%d-%H:%M:%S.%f")[:-3]
'1970-01-16-10:10:10.678'

-- 
Greg

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Re: Proper conversion of timestamp Igor Korot <ikorot01@gmail.com> - 2014-03-04 13:55 -0800
  Re: Proper conversion of timestamp Gregory Ewing <greg.ewing@canterbury.ac.nz> - 2014-03-05 17:06 +1300

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