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Groups > comp.lang.python > #56740
| Newsgroups | comp.lang.python |
|---|---|
| Date | 2013-10-12 04:03 -0700 |
| References | <f74fadac-e7c3-4419-9a65-ed6ecd5eb3fe@googlegroups.com> <mailman.1032.1381569606.18130.python-list@python.org> |
| Message-ID | <50950ef3-9fae-41cd-8a9a-4bd3ccc418c6@googlegroups.com> (permalink) |
| Subject | Re: Why isn't this code working how I want it to? |
| From | reubennottage@gmail.com |
On Saturday, October 12, 2013 10:20:24 AM UTC+1, Peter Otten wrote:
> reubennottage@gmail.com wrote:
>
>
>
> > I've been working on a program and have had to halt it due a slight
>
> > problem. Here's a basic version of the code:
>
> >
>
> > a = 'filled'
>
> > b = 'filled'
>
> > c = 'empty'
>
> > d = 'empty'
>
> > e = 'filled'
>
> > f = 'empty'
>
> > g = 'filled'
>
> >
>
> > testdict = {a : 'apple' , b : 'banana' , c : 'cake' , d : 'damson' , e :
>
> > 'eggs' , f : 'fish' , g : 'glue'}
>
>
>
> You have duplicate keys here, which becomes obvious when you spell out the
>
> values
>
>
>
> testdict = {"filled": "apple", "filled": "banana", ...}
>
>
>
> When you do that, the last value ("banana") wins, all others (e. g. "apple")
>
> are dropped.
>
>
>
> > Now what I want to do, is if a variable is filled, print it out. This
>
> > however isn't working how I planned. The following doesn't work.
>
> >
>
> > for fillempt in testdict:
>
> > if fillempt == 'filled':
>
> > print(testdict[fillempt])
>
> >
>
> > All this does though, is print glue, where I'd want it to print:
>
> >
>
> > apple
>
> > banana
>
> > eggs
>
> > glue
>
> >
>
> > Perhaps a dictionary isn't the best way to do this.. I wonder what else I
>
> > can do...
>
>
>
> A dictionary is spot-on, but you have to use the unique "apple",
>
> "banana",... as keys:
>
>
>
> >>> status = {"apple": "filled", "banana": "filled", "cake": "empty"}
>
> >>> for item in status:
>
> ... if status[item] == "filled":
>
> ... print(item)
>
> ...
>
> apple
>
> banana
>
>
>
> Could it be that you just confused dict keys with dict values?
This fixed it, thank you! I did think a dictionary was right; I never considered swapping the keys with the values, though. A simple 'fix, but it worked. You've been a great help.
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Why isn't this code working how I want it to? reubennottage@gmail.com - 2013-10-12 01:56 -0700
Re: Why isn't this code working how I want it to? Marco Nawijn <nawijn@gmail.com> - 2013-10-12 02:17 -0700
Re: Why isn't this code working how I want it to? Peter Otten <__peter__@web.de> - 2013-10-12 11:20 +0200
Re: Why isn't this code working how I want it to? reubennottage@gmail.com - 2013-10-12 04:03 -0700
Re: Why isn't this code working how I want it to? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2013-10-12 12:13 +0100
Re: Why isn't this code working how I want it to? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2013-10-12 10:39 +0100
Re: Why isn't this code working how I want it to? Jussi Piitulainen <jpiitula@ling.helsinki.fi> - 2013-10-12 12:50 +0300
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