How to create new python file with increament number, if doesn't exist?

Newsgroups	comp.lang.python
Date	2013-05-27 02:27 -0700
Message-ID	<3c99daa0-6f30-4cbf-b107-56021a324f7c@googlegroups.com> (permalink)
Subject	How to create new python file with increament number, if doesn't exist?
From	Avnesh Shakya <avnesh.nitk@gmail.com>

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hi,
   I want to create a new python file like 'data0.0.5', but if it is already exist then it should create 'data0.0.6', if it's also exist then next like 'data0.0.7'. I have done, but with range, please give me suggestion so that I can do it with specifying range.
I was trying this way and it's working also..

     i = 0
    for i in range(100):
        try:
            with open('Data%d.%d.%d.json'%(0,0,i,)): pass
            continue
        except IOError:
            edxCorrectDataFile = file('Data%d.%d.%d.json'%(0,0,i,), 'a+')
            break

But here I have defined range 100, Is it possible without range it create many required files?

Thanks

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How to create new python file with increament number, if doesn't exist? Avnesh Shakya <avnesh.nitk@gmail.com> - 2013-05-27 02:27 -0700
  Re: How to create new python file with increament number, if doesn't exist? Denis McMahon <denismfmcmahon@gmail.com> - 2013-05-27 10:49 +0000
    Re: How to create new python file with increament number, if doesn't exist? Avnesh Shakya <avnesh.nitk@gmail.com> - 2013-05-27 16:30 +0530
  Re: How to create new python file with increament number, if doesn't exist? jt@toerring.de (Jens Thoms Toerring) - 2013-05-27 11:13 +0000

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