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Re: Why is __root checked for in OrderedDict?

From Raymond Hettinger <python@rcn.com>
Newsgroups comp.lang.python
Subject Re: Why is __root checked for in OrderedDict?
Date 2011-04-07 12:30 -0700
Organization http://groups.google.com
Message-ID <2b653902-d1c3-4c0c-a788-65dce110e86b@f30g2000yqa.googlegroups.com> (permalink)
References <8dd32ba4-11c5-4326-8e1a-535decc7cfe4@glegroupsg2000goo.googlegroups.com>

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On Apr 7, 4:13 am, andrew cooke <and...@acooke.org> wrote:
> If you look at the code inhttp://hg.python.org/cpython/file/6adbf5f3dafb/Lib/collections/__init...the attribute __root is checked for, and only created if missing.  Why?
>
> I ask because, from what I understand, the __init__ method will only be called when the object is first being created, so __root will always be missing.

First of all, three cheers for reading the source code!

A user can call __init__() even after the OrderedDict instance has
already been created.  If so, the __root attribute will already exist
and the whole operation becomes equivalent to an update().

You can see the same behavior with regular dictionaries:

>>> d = dict(a=1, b=2)
>>> d.__init__(b=4, c=5)
>>> d
{'a': 1, 'c': 5, 'b': 4}


Raymond

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Why is __root checked for in OrderedDict? andrew cooke <andrew@acooke.org> - 2011-04-07 04:13 -0700
  Re: Why is __root checked for in OrderedDict? Raymond Hettinger <python@rcn.com> - 2011-04-07 12:30 -0700

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