How to re-implement the crypt.crypt function?

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From	Cosmia Luna <cosmius@gmail.com>
Newsgroups	comp.lang.python
Subject	How to re-implement the crypt.crypt function?
Date	Sat, 10 Mar 2012 11:33:36 -0800 (PST)
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I'm not searching for a full solution and only want to know how to use hashlib to create a equivalent string like 

crypt.crypt('123456', '$6$ds41p/9VMA.BHH0U') returns the string below. 

'$6$ds41p/9VMA.BHH0U$yv25s7jLxTRKLDNjIvT0Qc2jbcqdFRi5.PftO3cveTvjK49JhwCarIowOfrrNPD/PpYT3n6oNDIbjAONh8RXt1'

I tried:

from hashlib import sha512
from base64 import b64encode, b64decode

salt='ds41p/9VMA.BHH0U'
pwd='123456'

b64encode( sha512(pwd+salt).digest(), altchars='./' )
b64encode( sha512(salt+pwd).digest(), altchars='./' )
b64encode( sha512( pwd + b64decode(salt, altchars='./') ).digest(), altchars='./')
b64encode( sha512( b64decode(salt, altchars='./') + pwd ).digest(), altchars='./')

of course none of the four returns the value I want, 'yv25s7jLxTRKLDNjIvT0Qc2jbcqdFRi5.PftO3cveTvjK49JhwCarIowOfrrNPD/PpYT3n6oNDIbjAONh8RXt1', how can I get the value? I can't use crypt.crypt because of the consideration of cross-platform.

Thanks,
Cosmia

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How to re-implement the crypt.crypt function? Cosmia Luna <cosmius@gmail.com> - 2012-03-10 11:33 -0800
  Re: How to re-implement the crypt.crypt function? Roy Smith <roy@panix.com> - 2012-03-10 15:15 -0500
    Re: How to re-implement the crypt.crypt function? Christian Heimes <lists@cheimes.de> - 2012-03-10 21:36 +0100
      Re: How to re-implement the crypt.crypt function? Roy Smith <roy@panix.com> - 2012-03-10 15:41 -0500
        Re: How to re-implement the crypt.crypt function? Christian Heimes <lists@cheimes.de> - 2012-03-10 22:07 +0100
  Re: How to re-implement the crypt.crypt function? Christian Heimes <lists@cheimes.de> - 2012-03-10 21:16 +0100
    Re: How to re-implement the crypt.crypt function? Cosmia Luna <cosmius@gmail.com> - 2012-03-11 03:10 -0700
    Re: How to re-implement the crypt.crypt function? Cosmia Luna <cosmius@gmail.com> - 2012-03-11 03:10 -0700

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