odd difference calling function from class or instance variable

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From	GregS <not@my.real.address.com>
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Hello,

This is my first post here so please gently inform me of any etiquette 
breaches.

I'm seeing a behaviour I can't explain with Python 3.4.1 when I call a 
function via a reference stored in an object.

When I assign the reference as a class variable, the reference has 
__self__ set, too, so I get an extra argument passed to the function.  
If I assign the reference as an instance variable, then __self__ is 
unset so no extra argument.

Here's what I mean:

>>> def print_args(*args):
	print(args)
	
>>> class C:
	ref = None
	
>>> C.ref = print_args    # assign to class variable
>>> i = C()
>>> i.ref()     # call via class variable - get a 'self' argument passed
(<__main__.C object at 0x1071a05f8>,)
>>> i.ref = print_args   # assign to instance variable
>>> i.ref()     # call via instance variable: no arguments
()

If you look at i.ref.__self__ for the two cases, you'll see what's 
going on.  I've tried RTFMing but can't find the reason for the two 
behaviours.  Could someone provide an explanation for me, please?

Thanks,

Greg

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odd difference calling function from class or instance variable GregS <not@my.real.address.com> - 2014-08-13 10:06 +0100
  Re: odd difference calling function from class or instance variable Peter Otten <__peter__@web.de> - 2014-08-13 11:40 +0200
  Re: odd difference calling function from class or instance variable Chris Angelico <rosuav@gmail.com> - 2014-08-13 19:45 +1000
  Re: odd difference calling function from class or instance variable GregS <not@my.real.address.com> - 2014-08-13 11:20 +0100
    Re: odd difference calling function from class or instance variable Chris Angelico <rosuav@gmail.com> - 2014-08-13 20:29 +1000

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