Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #45679
| Newsgroups | comp.lang.python |
|---|---|
| Date | 2013-05-21 10:27 -0700 |
| Message-ID | <0f78102c-2e30-4858-ae62-b8d5cecfc345@googlegroups.com> (permalink) |
| Subject | More general way of generating PyODBC queries as a dict? |
| From | stackoverflowuser95@gmail.com |
Here are my averagely general class methods for creating a dictionary from the result of database queries:
def make_schema_dict(self):
schema = [i[2] for i in self.cursor.tables()
if i[2].startswith('tbl_') or i[2].startswith('vw_')]
self.schema = {table: {'scheme': [row.column_name for row
in self.cursor.columns(table)]}
for table in schema}
def last_table_query_as_dict(self, table):
return {'data': [{col: row.__getattribute__(col) for col in self.schema[table]['scheme']
if col != 'RowNum'} for row in self.cursor.fetchall()]}
Unfortunately as you can see, there are many complications.
For example, when multiple tables are queried; some hackish lambdas are required to generate the resulting dictionary.
Can you think of some more general methods?
(and yes I know this is against the PEP; and that this is also on SO)
Back to comp.lang.python | Previous | Next — Next in thread | Find similar | Unroll thread
More general way of generating PyODBC queries as a dict? stackoverflowuser95@gmail.com - 2013-05-21 10:27 -0700 Re: More general way of generating PyODBC queries as a dict? Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2013-05-21 19:33 -0400 Re: More general way of generating PyODBC queries as a dict? stackoverflowuser95@gmail.com - 2013-05-22 02:31 -0700
csiph-web