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| NNTP-Posting-Date | Fri, 19 Apr 2024 22:14:19 +0000 |
| From | steve <sgonedes1977@gmail.com> |
| Newsgroups | comp.lang.lisp |
| Subject | Re: how to map a variable to a list? |
| References | <u111j3$26d7d$1@dont-email.me> <O5sf1cOqAlzNMgIN7@bongo-ra.co> |
| Date | Fri, 19 Apr 2024 18:14:18 -0400 |
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Spiros Bousbouras <spibou@gmail.com> writes:
< On Mon, 10 Apr 2023 21:05:23 +0800
< Jinsong Zhao <jszhao@yeah.net> wrote:
>> Hi there,
>>
>> In the following code example,
>>
>> (defun a-test (lst)
>> (let ((a (elt lst 0))
>> (b (elt lst 1))
>> (c (elt lst 2)))
>> (+ a (- c b))))
>>
>> How to map local variable a, b, and c to the elements of lst? In my
>> actual code, the lst have 12 elements, and I have 12 named local
>> variables that appeared in the body with high frequency.
< Why is the above code not satisfactory ?
no idea, works for me.
(defun a-test (lst)
(let ((a (pop lst))
(b (pop lst))
(c (pop lst)))
(+ a (- c b))))
(a-test '(3 5 7))
(defun a-test2 (lst)
(let ((a (elt lst 0))
(b (elt lst 1))
(c (elt lst 2)))
(+ a (- c b))))
(a-test2 '(1 4 7))
show the code? might be helpful. 12 variables can be done with reduce
mapcar, depending on the operation.
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Re: how to map a variable to a list? steve <sgonedes1977@gmail.com> - 2024-04-19 18:14 -0400
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