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Re: need regular expression to replace part of result based on a search pattern

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On 7/11/2012 10:35 AM, Jimmy wrote:
> Have been having hard time to come up with the regular expression to replace the following..
>
> 1,"blaha",NULL,'N','Y','N','N',NULL
> 2,"blahb",NULL,'Y','Y','Y','N',NULL
> 3,"blahc",NULL,'N','N','N','N',NULL
>                          ^
>
> With all contents in column #6 (first column is column #1) to 'Y'?
>
> i.e. result
>
> 1,"blaha",NULL,'N','Y','Y','N',NULL
> 2,"blahb",NULL,'Y','Y','Y','N',NULL
> 3,"blahc",NULL,'N','N','Y','N',NULL
>                          ^
>
> Thanks,
> Jimmy
>

public class test {
     public static void main(String[] args) {
         String str = "3,\"blaha\",NULL,'N','N','N','N',NULL";

         System.out.println(str);

         String[] arr = str.split(",");
         if (arr[5].equals("'N'"))
             arr[5] = "'Y'";

         StringBuilder sb = new StringBuilder();
         for (int i=0; i<arr.length; i++) {
             sb.append(arr[i]);
             if (i != arr.length - 1)
                 sb.append(",");
         }
         System.out.println(sb);
     }
}

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Thread

need regular expression to replace part of result based on a search pattern Jimmy <jimmy_please@yahoo.com> - 2012-07-11 10:35 -0700
  Re: need regular expression to replace part of result based on a search pattern Roedy Green <see_website@mindprod.com.invalid> - 2012-07-11 15:24 -0700
  Re: need regular expression to replace part of result based on a search pattern Knute Johnson <nospam@rabbitbrush.frazmtn.com> - 2012-07-11 15:40 -0700
    Re: need regular expression to replace part of result based on a search pattern Daniele Futtorovic <da.futt.news@laposte-dot-net.invalid> - 2012-07-12 00:56 +0200
  Re: need regular expression to replace part of result based on a search pattern Roedy Green <see_website@mindprod.com.invalid> - 2012-07-11 21:21 -0700
  Re: need regular expression to replace part of result based on a search pattern Jimmy <jimmy_please@yahoo.com> - 2012-07-12 07:28 -0700
    Re: need regular expression to replace part of result based on a search pattern Eric Sosman <esosman@ieee-dot-org.invalid> - 2012-07-12 11:24 -0400
      Re: need regular expression to replace part of result based on a search pattern Joshua Cranmer <Pidgeot18@verizon.invalid> - 2012-07-12 11:42 -0400
      Re: need regular expression to replace part of result based on a search pattern Arne Vajhøj <arne@vajhoej.dk> - 2012-07-23 22:55 -0400
  Re: need regular expression to replace part of result based on a search pattern Leif Roar Moldskred <leifm@dimnakorr.com> - 2012-07-12 09:42 -0500
    Re: need regular expression to replace part of result based on a search pattern Gene Wirchenko <genew@ocis.net> - 2012-07-12 09:18 -0700
    Re: need regular expression to replace part of result based on a search pattern glen herrmannsfeldt <gah@ugcs.caltech.edu> - 2012-07-12 18:34 +0000
    Re: need regular expression to replace part of result based on a search pattern Arne Vajhøj <arne@vajhoej.dk> - 2012-07-23 22:53 -0400
  Re: need regular expression to replace part of result based on a search pattern Arne Vajhøj <arne@vajhoej.dk> - 2012-07-23 22:48 -0400
    Re: need regular expression to replace part of result based on a search pattern Arne Vajhøj <arne@vajhoej.dk> - 2012-07-25 17:37 -0400

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