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Groups > comp.lang.java.programmer > #11447
| From | Jeff Higgins <jeff@invalid.invalid> |
|---|---|
| Newsgroups | comp.lang.java.programmer |
| Subject | Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment |
| Date | 2012-01-17 21:33 -0500 |
| Organization | A noiseless patient Spider |
| Message-ID | <jf5ajc$arn$1@dont-email.me> (permalink) |
| References | <16090858.1983.1326812606093.JavaMail.geo-discussion-forums@prig11> <jf4asm$g9h$1@dont-email.me> <11466894.1272.1326851809373.JavaMail.geo-discussion-forums@prdh15> |
On 01/17/2012 08:56 PM, Mausam wrote: > On Tuesday, 17 January 2012 23:02:29 UTC+5:30, Jeff Higgins wrote: >> On 01/17/2012 10:03 AM, Mausam wrote: >>> I have a java class, whose contains a DocumentFragment. >>> >>> In the equals method of my class, I am converting the DocumentFragment to a String and comparing an equals on the String. >>> >>> I know this is not the best way, because "attributes" e.g can change order in Element of DocumentFragment, or e.g documents differ only in the sequence of unordered elements. >>> >>> So in such cases this equality will fail. >>> >>> Please suggest a better approach. >> A my class is equal to another my class if and only if ... > > Thanks Jeff, I understand what you mean. > > BTW, I was checking the API http://docs.oracle.com/javase/1.5.0/docs/api/org/w3c/dom/Node.html#isEqualNode%28org.w3c.dom.Node%29 > > The attributes NamedNodeMaps are equal. This is: they are both null, or they have the same length and for each node that exists in one map there is a node that exists in the other map and is equal, although not necessarily at the same index. > > > The childNodes NodeLists are equal. This is: they are both null, or they have the same length and contain equal nodes at the same index. Note that normalization can affect equality; to avoid this, nodes should be normalized before being compared. > > Here for attributes, they take care of "NOT necessarily at the same index" but in case of childNodes its not being taken care of. So if there is a sequence of unordered elements (<emp/><dept/> and<dept/><emp/> ) they will be treated as NOT equal. > > So either I iterate through each node and attribute and do a comparison. That's the fall back. But before that, I wanted to check the experts if there are better options. Yep. I based my hair trigger response upon the .equals(Object) of the "known implementing classes" of Node. Sorry. I'll be interested in finding out the "cost" associated with Arne Vajhøj's response.
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what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Mausam <mausamhere@gmail.com> - 2012-01-17 07:03 -0800
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Jeff Higgins <jeff@invalid.invalid> - 2012-01-17 12:32 -0500
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Mausam <mausamhere@gmail.com> - 2012-01-17 17:56 -0800
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Jeff Higgins <jeff@invalid.invalid> - 2012-01-17 21:33 -0500
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Arne Vajhøj <arne@vajhoej.dk> - 2012-01-17 21:56 -0500
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Arne Vajhøj <arne@vajhoej.dk> - 2012-01-17 18:38 -0500
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Arne Vajhøj <arne@vajhoej.dk> - 2012-01-17 21:55 -0500
Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment Mausam <mausamhere@gmail.com> - 2012-01-17 21:29 -0800
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