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Groups > comp.lang.java.programmer > #9317

Re: get path of a Jar file

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On 2011-10-24 22:07:18 +0200, Steven Simpson said:

> On 22/10/11 10:54, Philipp Kraus wrote:
>> String l_jarfile = 
>> Class.forName("class_within_the_jar").getResource("").toString();
>> l_jarfile        = l_jarfile.substring(9, 
>> l_jarfile.lastIndexOf(".jar!")) + ".jar";
>> 
>> This does not work on MS Windows systems (unix and OSX work correct 
>> with this code).
>> If the Jar files is stored under a path like "C:\Users\myuser\Java 
>> Files\myjar.jar" (with a space)
>> the JarFile-Object can't locate the file, because the space within the 
>> directory is changed to %20
> 
> Leaving aside the good questions of why, and whether these magic 
> constants are a good thing, I will address the decoding of % sequences: 
> Create a java.net.URI from the string, then create a java.io.File from 
> the URI.
> 
> import java.net.*;
> import java.io.*;
> 
> public class GetPath {
>      public static void main(String[] args) throws Exception {
>          Class<?>  clazz = Class.forName(args[0]);
>          URL clazzRes = clazz.getResource("");
>          String loc = clazzRes.toString();
>          System.out.println("Resource: " + loc);
>          URI stripped =
>              URI.create(loc.substring(4, loc.lastIndexOf(".jar!") + 4));
>          System.out.println("Stripped: " + stripped);
>          File result = new File(stripped);
>          System.out.println("Result: " + result);
>      }
> }
> 
> Lots of result checking omitted.

Thanks, the URI option is imho the best solution

Phil

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get path of a Jar file Philipp Kraus <philipp.kraus@flashpixx.de> - 2011-10-22 11:54 +0200
  Re: get path of a Jar file Lew <lewbloch@gmail.com> - 2011-10-22 08:52 -0700
  Re: get path of a Jar file Martin Gregorie <martin@address-in-sig.invalid> - 2011-10-22 21:19 +0000
  Re: get path of a Jar file Steven Simpson <ss@domain.invalid> - 2011-10-24 21:07 +0100
    Re: get path of a Jar file Philipp Kraus <philipp.kraus@flashpixx.de> - 2011-10-30 18:49 +0100

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