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| From | "dkoleary" <dkoleary@1:261/38.remove-k2r-this> |
| Subject | why does this work? |
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| Date | Thu, 09 Aug 2012 18:44:36 GMT |
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From: "dkoleary" <dkoleary@1:261/38.remove-qhs-this>
From: dkoleary <dkoleary@olearycomputers.com>
Hi;
New java programmer. So new, in fact, that I'm still working my way through
the O'Reilly Head First Java book. One of the end of chapter questions
involves identifying if a sample class will compile and what to do to make it
compile if it won't.
The sample class from chapter 4 is:
class XCopy
{ public static void main(String[] args)
{ int orig = 42;
XCopy x = new XCopy();
int y = x.go(orig);
System.out.println(orig + " " + y);
}
int go(int arg)
{ return arg * 2; }
}
The book says that it'll compile and run, displaying "42 84" and, sure enough,
it does:
$ javac XCopy.java
$ java XCopy
42 84
How come that isn't recursive? XCopy.main() instantiates a new XCopy.
Shouldn't that new XCopy instance also instantiate a new XCopy?
I was figuring this would run until the XCopy.go function tried returning a
number that wouldn't fit in int anymore... That's obviously not the case, but I
don't know why.
Can someone provide the missing concept?
Thanks.
Doug O'Leary
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Back to comp.lang.java.programmer | Previous | Next — Next in thread | Find similar | Unroll thread
why does this work? "dkoleary" <dkoleary@1:261/38.remove-k2r-this> - 2012-08-09 18:44 +0000
Re: why does this work? "Daniel Pitts" <daniel.pitts@1:261/38.remove-k2r-this> - 2012-08-09 18:44 +0000
Re: why does this work? "dkoleary" <dkoleary@1:261/38.remove-t9h-this> - 2012-08-10 18:38 +0000
Re: why does this work? "Eric Sosman" <eric.sosman@1:261/38.remove-k2r-this> - 2012-08-09 18:44 +0000
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