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| From | "Patricia Shanahan" <patricia.shanahan@1:261/38.remove-dpk-this> |
| Subject | Re: What is the command to do a power of a value |
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| Date | Tue, 31 Jul 2012 18:02:33 GMT |
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To: Patricia Shanahan From: Patricia Shanahan <pats@acm.org> On 7/30/2012 12:00 PM, Patricia Shanahan wrote: > To: Andreas Leitgeb > From: Patricia Shanahan <pats@acm.org> > > On 7/30/2012 6:22 AM, Andreas Leitgeb wrote: >> On Sun, 29 Jul 2012 21:28:11 -0700 (PDT), xvictoryeohx@gmail.com wrote: >>> C=L(1+i/100)power of n >> >> x ^ n = exp ( log(x) * n ) | x = (1 + i/100) >> = exp ( log( 1 + i/100 ) * n) >> = exp ( log1p ( i/100 ) * n) >> >> If you're doing more calculations with same interest-rate but >> different periods, then you may want to calculate >> double logBase = Math.log1p( i / 100 ); >> once, and use that for the individual calculations: >> C = L * Math.exp( logBase * n ) >> >> The gist of this response is, that for the kind of base (1+i/100), >> you better separate the pow operation out into log and exp, and >> actually use log1p on (i/100) instead of log on (1+i/100) for >> efficiency's and precision's sake. >> >> For "Math.log1p" see: >> http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html#log1p%28double% 2 > 9 >> > > I am curious about why you expect this to be more precise than: "The computed > result must be within 1 ulp of the exact result. Results must be > semi-monotonic." (From the pow description). Or do you know of cases where > Math.pow gets an over-large rounding error? > > Note that I am not disagreeing with your method for calculating a power of a > number slightly greater than 1, just questioning whether doing it explicitly > gets more precise answers than using Math.pow. I've thought about this some more, and I think I get it now. If i is reasonably small compared to 100, the 1 + i/100 addition loses several bits of precision. Patricia --- BBBS/Li6 v4.10 Dada-1 * Origin: Prism bbs (1:261/38) --- Synchronet 3.16a-Win32 NewsLink 1.98 Time Warp of the Future BBS - telnet://time.synchro.net:24
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What is the command to do a power of a value "xvictoryeohx" <xvictoryeohx@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "bugbear" <bugbear@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "glen herrmannsfeldt" <glen.herrmannsfeldt@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "xvictoryeohx" <xvictoryeohx@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Roedy Green" <roedy.green@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Andreas Leitgeb" <andreas.leitgeb@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Patricia Shanahan" <patricia.shanahan@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Patricia Shanahan" <patricia.shanahan@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "glen herrmannsfeldt" <glen.herrmannsfeldt@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Patricia Shanahan" <patricia.shanahan@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Andreas Leitgeb" <andreas.leitgeb@1:261/38.remove-dpk-this> - 2012-07-31 18:02 +0000
Re: What is the command to do a power of a value "Andreas Leitgeb" <andreas.leitgeb@1:261/38.remove-x1c-this> - 2012-07-31 20:07 +0000
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