Re: Help needed.

From	lewbloch <lewbloch@gmail.com>
Newsgroups	comp.lang.java.help
Subject	Re: Help needed.
Date	2011-07-30 16:19 -0700
Organization	http://groups.google.com
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lewbloch <lewbl...@gmail.com> wrote:
> (Note that 'Scanner#nextInLine()' takes a pattern, not a literal
> string, as its argument.)

Correction to my own post: The pattern is expressed as a literal
string, in Java terms.  What I meant was that the string is not
interpreted literally, but as a regular expression.  So the match in
your original example,

  myScanner.findInLine(".")

is to any single character, not just the '.' character.

--
Lew

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Help needed. neil furnival <neil.furnival@googlemail.com> - 2011-07-26 15:47 -0700
  Re: Help needed. markspace <-@.> - 2011-07-26 17:13 -0700
    Re: Help needed. neil furnival <neil.furnival@googlemail.com> - 2011-07-27 01:49 -0700
      Re: Help needed. lewbloch <lewbloch@gmail.com> - 2011-07-28 08:50 -0700
        Re: Help needed. lewbloch <lewbloch@gmail.com> - 2011-07-30 16:19 -0700
    Re: Help needed. Gene Wirchenko <genew@ocis.net> - 2011-07-27 11:33 -0700
  Re: Help needed. Roedy Green <see_website@mindprod.com.invalid> - 2011-07-26 22:09 -0700

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