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| From | joeNOSPAM@BEA.com.remove-dii-this |
| Subject | Re: java.sql.SQLException |
| Message-ID | <f1e109eb-22bc-41bf-8401-ffcc794bb163@40g2000prx.googlegroups.com> (permalink) |
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| Date | Wed, 27 Apr 2011 15:23:28 GMT |
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To: comp.lang.java.databases
Well it's clear that this procedure may not return anything if
it is passed a bogus food code. You need to try the JDBC code
I presented, eg:
findFoodCode.setString(1,input);
findFoodCode.setString(2,request.getParameter("country"));
boolean getResultSetNow = findFoodCode.execute();
int updateCount = -1;
while (true) { // handle all the in-line results from any stored
procedure or SQL
if (getResultSetNow) {
ResultSet r = findFoodCode.getResultSet();
ResultSetMetaData metaData = r.getMetaData();
int col_cmt = metaData.getColumnCount();
while (r.next()) {
// fully process result set before calling getMoreResults()
again!
for(int i=1;i<=col_cnt;i++)
{
out.print(r.getString(i)+";");
}
}
r.close();
} else {
updateCount = findFoodCode.getUpdateCount();
if (updateCount != -1) { // it's a valid update count
System.out.println("Reporting an update count of " +
updateCount);
}
}
if ((!getResultSetNow) && (updateCount == -1)) break; // done
with loop, finished all the returns
getResultSetNow = findFoodCode.getMoreResults();
}
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Re: java.sql.SQLException joeNOSPAM@BEA.com.remove-dii-this - 2011-04-27 15:23 +0000
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