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Re: Why does the -> operator exist ?

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Tim Rentsch <tr.17687@z991.linuxsc.com> writes:
> Keith Thompson <Keith.S.Thompson+u@gmail.com> writes:
>> Tim Rentsch <tr.17687@z991.linuxsc.com> writes:
>>> Keith Thompson <Keith.S.Thompson+u@gmail.com> writes:
>>>> Tim Rentsch <tr.17687@z991.linuxsc.com> writes:
>>>>> Keith Thompson <Keith.S.Thompson+u@gmail.com> writes:
>>>>>> [...] I would argue that using `->` rather than `.` when the
>>>>>> prefix is a pointer makes for more explicit code, which is a
>>>>>> good thing;  [...]
>>>>>
>>>>> More explicit is not always better.
>>>>
>>>> No, it isn't.
>>>>
>>>> If you had anything to say about this particular case (`->` being
>>>> more explicit than `.`, and whether it's better), this would have
>>>> been a good opportunity to say it.
>>>
>>> In the particular case of using '.' instead of '->', more
>>> explicit is not always better.
>>
>> That's a useless statement.
>
> No more useless than the statement from you that prompted
> the discussion.

My original statement, quoted above, was that using `->` rather than
`.` is more explicit and that that's a good thing.  That was and
is my opinion, applicable only to that particular case.  I've used
languages that use `.` for both (where the prefix can be either
a structure or a pointer), and haven't had any particular problem
with that.  I have a preference, but not a strong preference.

If I see `foo->bar` in C code, I know that `foo` is a pointer
expression pointing to a struct or union.  If I see `foo.bar`, I
know that `foo` is an expression of struct or union type.  I know
that without looking for the declaration.  I sometimes find it
useful to be able to understand something about a code fragment
without having to understand 100% of the context.

You apparently think that was a useless statement.  You apparently
thought it was important enough to comment on it.

You refuted a claim that explicit is *always* better.  Of course
I never said that, nor do I believe it.

I tried to invite you to expand on your statement.  Perhaps you think
that dropping `->` and using `.` for both structs and pointers (and
unions and union pointers) would have been better.  Perhaps you have
good reasons for your preference, assuming it is your preference.
Perhaps an explanation of those preferences would have been useful
and interesting.  Heck, I might even agree with you.

Instead, you chose to respond several times, adding exactly nothing
useful to the discussion.  Perhaps you expected us to understand
what you were thinking without you saying it.  If so, that was an
unrealistic expectation.

Let's stop this.

-- 
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
Will write code for food.
void Void(void) { Void(); } /* The recursive call of the void */

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Why does the  ->  operator exist ? Spiros Bousbouras <spibou@gmail.com> - 2023-06-27 09:12 +0000
  Re: Why does the  ->  operator exist ? felix@palmen-it.de (Felix Palmen) - 2023-06-27 15:01 +0200
    Re: Why does the  ->  operator exist ? Spiros Bousbouras <spibou@gmail.com> - 2023-06-27 14:09 +0000
      Re: Why does the  ->  operator exist ? Ben Bacarisse <ben.usenet@bsb.me.uk> - 2023-06-27 15:56 +0100
  Re: Why does the -> operator exist ? Bart <bc@freeuk.com> - 2023-06-27 16:06 +0100
    Re: Why does the -> operator exist ? Ben Bacarisse <ben.usenet@bsb.me.uk> - 2023-06-27 18:01 +0100
      Re: Why does the -> operator exist ? BGB <cr88192@gmail.com> - 2023-06-27 12:46 -0500
    Re: Why does the -> operator exist ? fir <profesor.fir@gmail.com> - 2023-08-09 00:08 -0700
      Re: Why does the -> operator exist ? fir <profesor.fir@gmail.com> - 2023-08-09 00:11 -0700
        Re: Why does the -> operator exist ? fir <profesor.fir@gmail.com> - 2023-08-09 00:23 -0700
  Re: Why does the  ->  operator exist ? Lew Pitcher <lew.pitcher@digitalfreehold.ca> - 2023-06-27 15:13 +0000
  Re: Why does the  ->  operator exist ? Kaz Kylheku <864-117-4973@kylheku.com> - 2023-06-27 15:30 +0000
    Re: Why does the -> operator exist ? Bart <bc@freeuk.com> - 2023-06-27 17:05 +0100
      Re: Why does the -> operator exist ? Kaz Kylheku <864-117-4973@kylheku.com> - 2023-06-27 17:11 +0000
  Re: Why does the -> operator exist ? BGB <cr88192@gmail.com> - 2023-06-27 10:54 -0500
  Re: Why does the  ->  operator exist ? Keith Thompson <Keith.S.Thompson+u@gmail.com> - 2023-06-27 12:23 -0700
    Re: Why does the  ->  operator exist ? Joe Pfeiffer <pfeiffer@cs.nmsu.edu> - 2023-06-27 15:33 -0600
    Re: Why does the  ->  operator exist ? Spiros Bousbouras <spibou@gmail.com> - 2023-06-28 16:31 +0000
      Re: Why does the  ->  operator exist ? Kaz Kylheku <864-117-4973@kylheku.com> - 2023-06-29 03:14 +0000
    Re: Why does the  ->  operator exist ? Tim Rentsch <tr.17687@z991.linuxsc.com> - 2023-07-20 18:57 -0700
      Re: Why does the  ->  operator exist ? Keith Thompson <Keith.S.Thompson+u@gmail.com> - 2023-07-20 19:49 -0700
        Re: Why does the  ->  operator exist ? Tim Rentsch <tr.17687@z991.linuxsc.com> - 2023-08-08 05:49 -0700
          Re: Why does the  ->  operator exist ? Keith Thompson <Keith.S.Thompson+u@gmail.com> - 2023-08-08 16:33 -0700
            Re: Why does the  ->  operator exist ? Tim Rentsch <tr.17687@z991.linuxsc.com> - 2023-08-14 04:34 -0700
              I love it... (Was: Why does the  ->  operator exist ?) gazelle@shell.xmission.com (Kenny McCormack) - 2023-08-14 12:41 +0000
              Re: Why does the  ->  operator exist ? Keith Thompson <Keith.S.Thompson+u@gmail.com> - 2023-08-14 15:10 -0700
                Re: Why does the  ->  operator exist ? Phil Carmody <pc+usenet@asdf.org> - 2023-08-15 23:00 +0300
                Re: Why does the  ->  operator exist ? Tim Rentsch <tr.17687@z991.linuxsc.com> - 2023-08-16 05:29 -0700
      Re: Why does the  ->  operator exist ? Kaz Kylheku <864-117-4973@kylheku.com> - 2023-07-22 05:39 +0000
  Re: Why does the -> operator exist ? Andrey Tarasevich <andreytarasevich@hotmail.com> - 2023-06-28 14:16 -0700

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