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| From | Randy Yates <randyy@garnerundergroundinc.com> |
|---|---|
| Newsgroups | comp.dsp |
| Subject | Re: How to downsample this signal? |
| Organization | Garner Underground, Inc. |
| References | (5 earlier) <ofcf3l$6o8$1@dont-email.me> <87h90mqfwv.fsf@garnerundergroundinc.com> <ofe7r4$oc4$1@dont-email.me> <8760h0pw02.fsf@garnerundergroundinc.com> <591b3f08.489072937@news.eternal-september.org> |
| Date | 2017-05-16 15:35 -0400 |
| Message-ID | <87vap0mw6m.fsf@garnerundergroundinc.com> (permalink) |
eric.jacobsen@ieee.org writes: > On Tue, 16 May 2017 13:11:25 -0400, Randy Yates > <randyy@garnerundergroundinc.com> wrote: > >>rickman <gnuarm@gmail.com> writes: >> >>> On 5/15/2017 11:49 AM, Randy Yates wrote: >>>> rickman <gnuarm@gmail.com> writes: >>>> >>>>> On 5/15/2017 1:21 AM, Piotr Wyderski wrote: >>>>>> rickman wrote: >>>>>> >>>>>>> Are the 248 words for data or also program? >>>>>> >>>>>> Data only, there are dedicated code memories. The control part >>>>>> is totally crazy: there are two separate code memories working >>>>>> in parallel (they take both paths simultaneosly in order to >>>>>> provide instructions with no delay in the case of a branch). >>>>>> But there is no such thing as a program counter, the code >>>>>> memories store instructions at consecutive addresses without >>>>>> any deeper structure. A run of instructions is called a block >>>>>> and is ended with the presence of a jump instruction. There >>>>>> is also a third control memory which stores the information >>>>>> where the i-th block begins and to which j-th state the FSM >>>>>> should go in the case of a branch. In short, hardware basic >>>>>> blocks. The data path is a VLIW with exposed pipelining, >>>>>> which adds fun. >>>>>> >>>>>>> That should be plenty of room for coefficients. >>>>>> >>>>>> But doesn't the FIR require a lot of cells for >>>>>> the past data values? >>>>> >>>>> Like I said, I wrote this a long time ago, so I am not the resource to >>>>> be asking. I can't picture how it works, but I specifically remember >>>>> NOT needing to store previous data inputs. I am thinking you store >>>>> outputs which will be fewer because of the decimation. As the input >>>>> data comes in the output samples can be built up and when one is >>>>> complete it is outputted and replaced by a new one. >>>>> >>>>> But read a proper reference. If I wasn't busy today I'd dig this up >>>>> for you. >>>> >>>> Yes you do need to store N-1 previous inputs (plus 1 current input) for >>>> a length N polyphase FIR decimation by M. Just think first principles: >>>> for any output y[k], you need N inputs to compute it, even if k = n*M. >>> >>> I am pretty sure that conclusion is not correct. When I was asked to >>> implement a polyphase filter that was the part I had trouble getting >>> my head around but finally understood how it worked. At the time this >>> was being done on a very early DSP chip with very limited memory, so >>> storing the N-1 previous samples was not an option. The guy >>> presenting the problem to me was the classic engineer who could read >>> and understand things, but couldn't explain anything to other people. >>> So I had to take the paper he gave me and finally figure it out for >>> myself. >>> >>> I will dig around when I get a chance and figure out exactly how this >>> worked. But the basic idea is that instead of saving multiple inputs >>> and calculating the outputs one at a time (iterating over the stored >>> inputs) - as each input comes in it is iterated over the stored >>> outputs and each output is ... well output, when it has been fully >>> calculated. Since there are fewer outputs than inputs (by the >>> decimation factor of M) you store fewer outputs than you would inputs. >>> >>> This is not hard to understand if you just stop thinking it *has* to >>> be the way you are currently seeing it. (shown here with simplified >>> notation since it is too messy to show the indexes with decimation) >>> >>> y(k) = a(0)x(i) + a(1)x(i-1) + a(2)x(i-2) + ... >>> y(k+1) = a(0)x(i+1) + a(1)x(i) + a(2)x(i-1) + ... >>> y(k+2) = a(0)x(i+2) + a(1)x(i+1) + a(2)x(i) + ... >>> y(k+3) = a(0)x(i+3) + a(1)x(i+2) + a(2)x(i+1) + ... >>> >>> Instead of thinking you have to calculate all the terms of y(k) at one >>> time (and so store the last N*M values of x), consider that when x(i) >>> arrives, you can calculate the x(i) terms and add them into y(k) >>> (which is then output) and y(k+1), y(k+2)... This allows the storage >>> of fewer values by a factor of M. It does require more memory fetches >>> than the standard MAC calculation since you have to fetch not only the >>> coefficient and the input, but also the intermediate output value >>> being calculated on each MAC operation. >>> >>> Maybe I won't have to dig it up. I'm pretty sure this is how it >>> worked. It ties in nicely with the "polyphase" aspect to allow a >>> minimum number of calculations on arrival of each input since not all >>> the coefficients are used on each input. So the coefficients are >>> divided into "phases" (N/M coefficients) with only one phase used for >>> any given input sample. >> >>Counter-example: Consider M = 8, N = 8 (8 coefficients and decimating by >>8). Then each output y(k) depends on x(k*M + n), 0 < n < M - 1, and thus >>the sets of input values for different outputs are disjoint. > > How each input will be used for each output is known when that input > arrives, so if all possible ouputs for that input have their own > partial product accumulator, the input can be multiplied by the > various coefficients for each partial product and accumulated in each, > and then forgotten. > > It's just another way to do it, but it can save a lot of hardware in a > hardware implementation, especially in an FPGA where the > multiply-accumulators are already built and just laying around, > anyway. So are you asserting this is not a counter-example? To state that an N-tap FIR decimator does not require all N inputs for an output at time k is, in general, not true, as I have shown. I believe what you are claiming is that IN CERTAIN CASES you can get away with not using all N inputs at output time k. That I can agree with. However, neither you nor Rick put a constraint on your assertion. And I can see that, in certain situations, this can be mo' better, namely when you have one or more MACs sitting around not being used (as you said) and N > M. But in general it hardly seems a storage saver as a MAC is a storage element+. -- Randy Yates, Embedded Firmware Developer Garner Underground, Inc. 866-260-9040, x3901 http://www.garnerundergroundinc.com
Back to comp.dsp | Previous | Next — Previous in thread | Next in thread | Find similar
How to downsample this signal? Piotr Wyderski <peter.pan@neverland.mil> - 2017-05-13 09:23 +0200
Re: How to downsample this signal? Evgeny Filatov <filatov.ev@mipt.ru> - 2017-05-13 15:42 +0300
Re: How to downsample this signal? bitterlemon40@yahoo.ie - 2017-05-13 07:53 -0700
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-13 11:48 -0400
Re: How to downsample this signal? Randy Yates <yates@digitalsignallabs.com> - 2017-05-13 12:58 -0400
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-13 16:04 -0400
Re: How to downsample this signal? Randy Yates <yates@digitalsignallabs.com> - 2017-05-14 14:19 -0400
Re: How to downsample this signal? Piotr Wyderski <peter.pan@neverland.mil> - 2017-05-15 00:42 +0200
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-15 00:46 -0400
Re: How to downsample this signal? Piotr Wyderski <peter.pan@neverland.mil> - 2017-05-15 07:21 +0200
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-15 10:51 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-15 11:49 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-15 17:20 -0400
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-16 02:59 -0400
Re: How to downsample this signal? eric.jacobsen@ieee.org - 2017-05-16 15:59 +0000
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-16 15:36 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-16 13:11 -0400
Re: How to downsample this signal? eric.jacobsen@ieee.org - 2017-05-16 18:08 +0000
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-16 15:35 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-16 15:45 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-16 15:50 -0400
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-16 21:36 -0400
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-16 15:35 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-16 15:36 -0400
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-16 15:40 -0400
Re: How to downsample this signal? rickman <gnuarm@gmail.com> - 2017-05-16 22:06 -0400
Re: How to downsample this signal? Randy Yates <yates@digitalsignallabs.com> - 2017-05-17 01:25 -0400
Re: How to downsample this signal? Evgeny Filatov <filatov.ev@mipt.ru> - 2017-05-15 14:51 +0300
Re: How to downsample this signal? Randy Yates <randyy@garnerundergroundinc.com> - 2017-05-15 10:37 -0400
Re: How to downsample this signal? makolber@yahoo.com - 2017-05-15 06:27 -0700
Re: How to downsample this signal? Piotr Wyderski <peter.pan@neverland.mil> - 2017-05-15 20:39 +0200
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