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Groups > comp.databases.ms-sqlserver > #1541
| Newsgroups | comp.databases.ms-sqlserver |
|---|---|
| Date | 2013-08-14 02:18 -0700 |
| References | <492c4449-7052-4337-a9b1-ddee6371ba20@googlegroups.com> |
| Message-ID | <b189b500-6a6e-49bf-abac-3be46e0164fe@googlegroups.com> (permalink) |
| Subject | Re: how many new IDs participated |
| From | Ross Presser <rpresser@gmail.com> |
On Tuesday, August 13, 2013 9:43:44 PM UTC-4, migurus wrote: > I have a series of Customer ID / Date records showing participation of customers on the daily basis. I need to find out how many new customers participated each day. [snip] > Any ideas? I was trying to self-join but can not quite wrap my brain around it. > > Thanks in advance. WITH X1 AS ( SELECT ID, MIN(DT) AS FirstDT FROM @T AS T GROUP BY ID ), X2 AS ( SELECT DISTINCT DT FROM @T AS T ) SELECT X2.DT, COUNT(X1.ID) FROM X2 LEFT JOIN X1 ON X2.DT = X1.FirstDT GROUP BY X2.DT DT ---------- ----------- 2013-08-07 2 2013-08-08 0 2013-08-09 1 2013-08-12 0 2013-08-13 1 Warning: Null value is eliminated by an aggregate or other SET operation. (5 row(s) affected) The value for 2013-08-09 is accurate; look closely at your data, 332551 is represented twice on that day.
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how many new IDs participated migurus <migurus@yahoo.com> - 2013-08-13 18:43 -0700
Re: how many new IDs participated Ross Presser <rpresser@gmail.com> - 2013-08-14 02:18 -0700
Re: how many new IDs participated migurus <migurus@yahoo.com> - 2013-08-14 13:27 -0700
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