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Groups > comp.databases.ms-sqlserver > #1969
| From | Erland Sommarskog <esquel@sommarskog.se> |
|---|---|
| Newsgroups | comp.databases.ms-sqlserver |
| Subject | Re: to show full set of two tables |
| Date | 2016-07-26 11:51 +0200 |
| Organization | Erland Sommarskog |
| Message-ID | <XnsA651789C32425Yazorman@127.0.0.1> (permalink) |
| References | <f4792cbb-d224-4cc0-ab82-b81d0cbcd87d@googlegroups.com> |
M.G. (michael@gurfinkel.us) writes: > There is an assignment schedule where several entities are assigned on a > daily basis, in ID/DATE simple fashion. > > I need to report all IDS per every date in the work dates calendar, > including instances where no assignment exists: >... > > It works OK, but I suspect my solution could (and should) be simplified. > Any ideas? So two things strikes me as odd here. 1) If the result set is supposed to show whether there is an assignment for a certain ID on a certain date, I would expect three columns: date, id and a yes/no column. Now there are multiple rows with NULL on the same date if there is no assignment at all. 2) I would expect there to be a table to hold the IDs as such. In that case the SELECT DISTINCT in the CTE could be replace with a straight SELECT from that table. Else, this is the typical pattern for this type of query. -- Erland Sommarskog, Stockholm, esquel@sommarskog.se
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to show full set of two tables "M.G." <michael@gurfinkel.us> - 2016-07-25 18:47 -0700 Re: to show full set of two tables Erland Sommarskog <esquel@sommarskog.se> - 2016-07-26 11:51 +0200
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