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Groups > comp.databases.ms-sqlserver > #1926
| Newsgroups | comp.databases.ms-sqlserver |
|---|---|
| Date | 2015-07-18 08:59 -0700 |
| References | <c81001e7-790a-4f44-9279-48acd08a8392@googlegroups.com> <XnsA4D3DEE656C88Yazorman@127.0.0.1> |
| Message-ID | <80e821e6-054f-430a-8b14-6a86e7cb7219@googlegroups.com> (permalink) |
| Subject | Re: Regular expression question |
| From | rja.carnegie@gmail.com |
On Friday, 10 July 2015 20:54:45 UTC+1, Erland Sommarskog wrote: > (rja.carnegie@gmail.com) writes: > > SQL Server 2005. The second and third versions of the > > following statement print 'Yes', which is unexpected. > > > > The intention is to test whether the first term is > > a compound house "number" such as '1A' or '1-3'. > > Either / or \ I thought would perform an "escape" > > in the pattern string, to treat a following special > > character as the literal character, but it seems to > > perform correctly without that, not with. So this > > test may be not doing what I think it is, at all. > > And the question is: uh? ;-) > > > > IF ( '15' LIKE N'[1-9]%[-A-Z]%' ) PRINT 'Yes 1' > > > > IF ( '15' LIKE N'[1-9]%[/-A-Z]%' ) PRINT 'Yes 2' > > > > IF ( '15' LIKE N'[1-9]%[\-A-Z]%' ) PRINT 'Yes 3' > > > > The patterns [/-A-Z] and [\-A-Z] means "all characters in the range from > (back)slash to A, as well as hyphen and Z. This will match 15 if digits > are in this range in your collation. > > There is no predefined escape character for LIKE, but you can specify one > explictly: > > IF '15%' LIKE '[1-9][0-9]!%' ESCAPE '!' PRINT 'Yup' > IF '15$' LIKE '[1-9][0-9]!%' ESCAPE '!' PRINT 'Nope' > > You can also use it inside brackets: > > IF '10%' LIKE '[1-9][0!-9]!%' ESCAPE '!' PRINT 'Yup' > IF '11%' LIKE '[1-9][0!-9]!%' ESCAPE '!' PRINT 'Nope' > IF '1-%' LIKE '[1-9][0!-9]!%' ESCAPE '!' PRINT 'Yup' > IF '18%' LIKE '[1-9][0!-9]!%' ESCAPE '!' PRINT 'Nope' > IF '19%' LIKE '[1-9][0!-9]!%' ESCAPE '!' PRINT 'Yup' I forgot to thank you for explaining this. I wonder where I picked up the idea that you just use a standard escape character. Maybe it was described and demonstrated in the next line, that I didn't read.
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Regular expression question rja.carnegie@gmail.com - 2015-07-10 08:05 -0700
Re: Regular expression question Erland Sommarskog <esquel@sommarskog.se> - 2015-07-10 21:54 +0200
Re: Regular expression question rja.carnegie@gmail.com - 2015-07-18 08:59 -0700
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