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counting in DOS

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  counting in DOS Francky Leyn <Francky@Leyn.eu> - 2015-07-03 07:01 +0200
    Re: counting in DOS Todd Vargo <tlvargo@sbcglobal.netz> - 2015-07-03 02:52 -0400
      Re: counting in DOS Todd Vargo <tlvargo@sbcglobal.netz> - 2015-07-09 17:40 -0400
        Re: counting in DOS Francky Leyn <Francky@Leyn.eu> - 2015-07-10 18:41 +0200
          Re: counting in DOS Todd Vargo <tlvargo@sbcglobal.netz> - 2015-07-10 12:59 -0400

#8 — counting in DOS

Hello,

I have a script crop_odd.bat which contains:
i_view32 %1.jpg /crop=(0,0,1634,2160,0) /convert=%1.jpg
If one types:
crop_odd 113
then this is expanded to:
i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert=113.jpg

Now I want to extend this script with:

1) If I type
    crop_odd 113
    I want this seen expanded to:
    i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert="p. 113.jpg"
    How must the script be expanded, so that this is the result?

2) If the script crop_even is:
    i_view32 %1.jpg /crop=(0,0,1634,2160,0) /convert=%1.jpg
    then typing
    crop_even 113
    will be expanded into
    i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert=113.jpg
    Instead of this, I want it expanded into:
    i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert="p. 114.jpg"

    In order to obtain this 2 thing must be present:
    a) proper quoting like in 1).
    b) one must be able to count: 113 -> 114

    This is not all. Consider the following:
    crop_even 003
    This should be expanded to
    i_view32 003.jpg /crop=(0,0,1634,2160,0) /convert="p. 004.jpg"

    The same for:
    crop_even 013
    which must be expanded into:
    i_view32 013.jpg /crop=(0,0,1634,2160,0) /convert="p. 014.jpg"

How to realize all the above?

Best regards,

Francky Leyn

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#9

On 7/3/2015 1:01 AM, Francky Leyn wrote:
> Hello,
>
> I have a script crop_odd.bat which contains:
> i_view32 %1.jpg /crop=(0,0,1634,2160,0) /convert=%1.jpg
> If one types:
> crop_odd 113
> then this is expanded to:
> i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert=113.jpg
>
> Now I want to extend this script with:
>
> 1) If I type
>     crop_odd 113
>     I want this seen expanded to:
>     i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert="p. 113.jpg"
>     How must the script be expanded, so that this is the result?
>
> 2) If the script crop_even is:
>     i_view32 %1.jpg /crop=(0,0,1634,2160,0) /convert=%1.jpg
>     then typing
>     crop_even 113
>     will be expanded into
>     i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert=113.jpg
>     Instead of this, I want it expanded into:
>     i_view32 113.jpg /crop=(0,0,1634,2160,0) /convert="p. 114.jpg"
>
>     In order to obtain this 2 thing must be present:
>     a) proper quoting like in 1).
>     b) one must be able to count: 113 -> 114
>
>     This is not all. Consider the following:
>     crop_even 003
>     This should be expanded to
>     i_view32 003.jpg /crop=(0,0,1634,2160,0) /convert="p. 004.jpg"
>
>     The same for:
>     crop_even 013
>     which must be expanded into:
>     i_view32 013.jpg /crop=(0,0,1634,2160,0) /convert="p. 014.jpg"
>
> How to realize all the above?
>
> Best regards,
>
> Francky Leyn

The name of your batch files are a bit deceiving, but from your 
description above, the following code seems to be your goal. Personally, 
I would have named them crop_same.bat and crop_incr.bat but that's just me.


Change crop_odd.bat to this,
i_view32 %1.jpg /crop=(0,0,1634,2160,0) /convert="p. %1.jpg"


Change crop_even.bat to this,
@echo off
set "n=1%1"
set /a n+=1
set "n=%n:~1%"
i_view32 %1.jpg /crop=(0,0,1634,2160,0) /convert="p. %n%.jpg"


Give these two a try and post back to let us know if it does what you 
wanted.

-- 
Todd Vargo
(Post questions to group only. Remove "z" to email personal messages)

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#11

On 7/9/2015 10:54 AM, Francky Leyn wrote:
> Hello Todd,
>
> The script is now called crop_double.bat :
>
> @echo off
> set "n=1%1"

Creates a variable named "n" and stores the value of %1, prefixed with a 
1. This is done because some of your file numbers begin with a zero.

So for 041, the value stored is 1041.


> set /a n-=1

The /a switch indicates an mathematical operation, in this case it 
subtracts 1 from the value. Without the leading 1, it would provide 
incorrect results including removal of the leading zero(s).

So the value stored becomes 1040.

> set "n=%n:~1%"

This removes the leading 1, so the value stored becomes 040.


> mkdir "%CD%\02 crop"
> i_view32 "%CD%\01 src\%1.jpg" /crop=(0,0,1634,2160,0) /convert="%CD%\02
> crop\p. %n%.jpg"
> i_view32 "%CD%\01 src\%1.jpg" /crop=(1634,0,1634,2160,0)
> /convert="%CD%\02 crop\p. %1.jpg"
>
> It does perfecly what I want.
>
> If  have a jpg file 041.jpg in "01 src",
> and if type at the prompt:
> crop_double 041
> then 2 jpg files are generated:
> "02 crop\p. 040.jpg" and
> "02 crop\p. 041.jpg"
>
> However, I would like to understand the set commands.
> Could you explain in detail what the different set commands do?
>
> Best regards,
>
> Francky


-- 
Todd Vargo
(Post questions to group only. Remove "z" to email personal messages)

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#12

On 7/9/2015 11:40 PM, Todd Vargo wrote:
> On 7/9/2015 10:54 AM, Francky Leyn wrote:
>> Hello Todd,
>>
>> The script is now called crop_double.bat :
>>
>> @echo off
>> set "n=1%1"
>
> Creates a variable named "n" and stores the value of %1, prefixed with a
> 1. This is done because some of your file numbers begin with a zero.
>
> So for 041, the value stored is 1041.
>
>
>> set /a n-=1
>
> The /a switch indicates an mathematical operation, in this case it
> subtracts 1 from the value. Without the leading 1, it would provide
> incorrect results including removal of the leading zero(s).
>
> So the value stored becomes 1040.
>
>> set "n=%n:~1%"
>
> This removes the leading 1, so the value stored becomes 040.


Can go a bit more in detail?
Why the 2 % signs?
What means :~ ?


>> mkdir "%CD%\02 crop"
>> i_view32 "%CD%\01 src\%1.jpg" /crop=(0,0,1634,2160,0) /convert="%CD%\02
>> crop\p. %n%.jpg"
>> i_view32 "%CD%\01 src\%1.jpg" /crop=(1634,0,1634,2160,0)
>> /convert="%CD%\02 crop\p. %1.jpg"
>>
>> It does perfecly what I want.
>>
>> If  have a jpg file 041.jpg in "01 src",
>> and if type at the prompt:
>> crop_double 041
>> then 2 jpg files are generated:
>> "02 crop\p. 040.jpg" and
>> "02 crop\p. 041.jpg"
>>
>> However, I would like to understand the set commands.
>> Could you explain in detail what the different set commands do?
>>
>> Best regards,
>>
>> Francky
>
>

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#13

On 7/10/2015 12:41 PM, Francky Leyn wrote:
> On 7/9/2015 11:40 PM, Todd Vargo wrote:
>> On 7/9/2015 10:54 AM, Francky Leyn wrote:
>>> Hello Todd,
>>>
>>> The script is now called crop_double.bat :
>>>
>>> @echo off
>>> set "n=1%1"
>>
>> Creates a variable named "n" and stores the value of %1, prefixed with a
>> 1. This is done because some of your file numbers begin with a zero.
>>
>> So for 041, the value stored is 1041.
>>
>>
>>> set /a n-=1
>>
>> The /a switch indicates an mathematical operation, in this case it
>> subtracts 1 from the value. Without the leading 1, it would provide
>> incorrect results including removal of the leading zero(s).
>>
>> So the value stored becomes 1040.
>>
>>> set "n=%n:~1%"
>>
>> This removes the leading 1, so the value stored becomes 040.
>
>
> Can go a bit more in detail?
> Why the 2 % signs?
> What means :~ ?

Type SET/? at command prompt for extensive help information.


>
>
>>> mkdir "%CD%\02 crop"
>>> i_view32 "%CD%\01 src\%1.jpg" /crop=(0,0,1634,2160,0) /convert="%CD%\02
>>> crop\p. %n%.jpg"
>>> i_view32 "%CD%\01 src\%1.jpg" /crop=(1634,0,1634,2160,0)
>>> /convert="%CD%\02 crop\p. %1.jpg"
>>>
>>> It does perfecly what I want.
>>>
>>> If  have a jpg file 041.jpg in "01 src",
>>> and if type at the prompt:
>>> crop_double 041
>>> then 2 jpg files are generated:
>>> "02 crop\p. 040.jpg" and
>>> "02 crop\p. 041.jpg"
>>>
>>> However, I would like to understand the set commands.
>>> Could you explain in detail what the different set commands do?
>>>
>>> Best regards,
>>>
>>> Francky
>>
>>
>


-- 
Todd Vargo
(Post questions to group only. Remove "z" to email personal messages)

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