Path: csiph.com!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Sylvia Else Newsgroups: sci.physics.relativity Subject: Re: Question For Relativity 'Experts'. Date: Sun, 25 Sep 2016 11:55:45 +1000 Lines: 41 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 7bit X-Trace: individual.net XROtkLtGNJ672TaGYow0vARWTk5LD5/1YItafVXZydUgJl7YnG Cancel-Lock: sha1:1kTd+IuDI8N0nciAiuqsphy/O8s= User-Agent: Mozilla/5.0 (Windows NT 6.1; rv:38.0) Gecko/20100101 Thunderbird/38.3.0 In-Reply-To: Xref: csiph.com sci.physics.relativity:393679 On 25/09/2016 6:13 AM, HGWilson, DSc. wrote: > On 24/09/16 22:12, Sylvia Else wrote: >> On 24/09/2016 10:04 PM, HGWilson, DSc. wrote: > . >>>> >>>> Since something moving at the speed of light relative to one >>>> observer is >>>> also moving at the speed of light relative to all other observers, >>>> there's nothing it needs to do, or know. >>> >>> There are no bloody observers you dimwit. There is an accelerating light >>> source and some photons. >>> >>> If you can't give a reason why the second photon does not do exactly >>> what the first one did....that is, move at c relative to its source.... >>> then I can only assume you don't have one. >> >> It does move at c relative to its source. >> >> But that doesn't mean that it will catch up with the previous pulse, >> because of the way that velocities combine (i.e. not by simple addition). > > Ok, let us introduce an arbitrary observer who will eventually receive > the light pulses. Quite obviously, his presence cannot affect the way > the pulses leave the source or the speed at which either of them > subsequently travels. To claim that the chance existence of his obscure > frame of reference is the sole determinant of the speeds of the pulses > is nonsensical. The only true reference is the source itself. > > Sometimes it seems you won't take yes for an answer. You insist that the light pulse moves at c relative to the source. I agree. What's the next step in your argument? Sylvia.