Path: csiph.com!1.us.feeder.erje.net!feeder.erje.net!1.eu.feeder.erje.net!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Sylvia Else Newsgroups: sci.physics.relativity Subject: Re: How Stupid Can a Dingleberry Get? Date: Tue, 28 Jun 2016 22:27:03 +1000 Lines: 36 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 7bit X-Trace: individual.net Eo7+iGc8n4NxnYGDtSgACQiM1s/rarOSbFHIR7rGDzSXT4RxXA Cancel-Lock: sha1:DgOVKgkgEjb+tvWryHebVmhkEY8= User-Agent: Mozilla/5.0 (Windows NT 6.1; rv:38.0) Gecko/20100101 Thunderbird/38.3.0 In-Reply-To: Xref: csiph.com sci.physics.relativity:386798 On 28/06/2016 8:21 PM, HGWilson, DSc. wrote: > A rod has a light source and a clock at each end. > > C1_________L__________C2 > > Light signals are sent from one end to the other and the clocks are > adjusted by an attached observer so they are set to measure the travel > times in opposite direction to be equal, as they must be due to > symmetry. Their readings when the signals leave and arrive are recorded > and are clearly visible. > > An observer moving past the rod says the clocks are wrongly set because > according to his university text, the signals are moving at c in his > frame and the rod is moving. Therefore the signals take different times > to transit the rod. > > C1_________L__________C2 > O2>v > > O2 says the signals take times L'/(c+/-v) to cross the rod in the two > directions...when it is obvious that the times must be equal. > > Q) How can every passing observer have an influence on what the clocks > should read? > Need I say more? Yes. Since the moving observer cannot be at C1 when the light signal reaches it, and also at C2 when the other light signal reaches it, the observer has to observe at least one of these events from a distance, and then extrapolate when the event occurred based on its distance and the speed of light. So you need to discuss the ramifications of that. Sylvia.