Path: csiph.com!weretis.net!feeder6.news.weretis.net!nntp.club.cc.cmu.edu!micro-heart-of-gold.mit.edu!newsswitch.lcs.mit.edu!nntp.TheWorld.com!.POSTED!not-for-mail From: moroney@world.std.spaamtrap.com (Michael Moroney) Newsgroups: sci.math Subject: Re: called Double Gyres Re: New Chemistry Table-- two superimposed cones Date: Sun, 18 Mar 2018 05:01:31 +0000 (UTC) Organization: The World : www.TheWorld.com : Since 1989 Lines: 63 Message-ID: References: <5b9bd38c-896e-421f-9eb8-ad951290ed8b@googlegroups.com> <2809ad26-fe8a-4c8f-abb4-9f43751c9846@googlegroups.com> <0e356fd5-8107-409d-9488-3db6e7fd193b@googlegroups.com> <33d57e8c-7bc7-49f8-976e-d6b60431cc28@googlegroups.com> NNTP-Posting-Host: shell01.theworld.com X-Trace: pcls7.std.com 1521349291 13698 192.74.137.71 (18 Mar 2018 05:01:31 GMT) X-Complaints-To: abuse@TheWorld.com NNTP-Posting-Date: Sun, 18 Mar 2018 05:01:31 +0000 (UTC) User-Agent: nn/6.6.5 Xref: csiph.com sci.math:408801 Archimedes Plutonium writes: [nothing] >Michael Moroney wrote >4:46 PM (2 hours ago) >>Oh, so you finally have a [proof the ellipse is not a conic section?] Archie posted that snippet yet again, even though it's a week old now. At least 10 times in (at least) two groups. Guess it must really bug him that he still has no proof the ellipse is not a conic section. It continues to amuse me how kooks do something totally illogical, and then do it over and over again. Like how Archie quotes a contextless snippet of what I wrote, to the wrong topic, and frequently in the wrong group, and says nothing about it himself. And he keeps doing that. Why? Dementia? Autism? Senility? OCD? Schizophrenia? Or maybe he just wants to see this proof that the ellipse can be a conic section again. Below you will find a simple *proof* that shows that certain conic sections are ellipses. Some preliminaries: Top view of the conic section and depiction of the coordinate system used in the proof: ^ x | -+- <= x=h .' | `. . | . | | | ' | ' `. | .' y <----------+ <= x=0 Cone (side view): . /|\ / | \ /b | \ /---+---' <= x = h / |' \ / ' | \ / ' | \ x = 0 => '-------+-------\ / a | \ Proof: r(x) = a - ((a-b)/h)x and d(x) = a - ((a+b)/h)x, hence y(x)^2 = r(x)^2 - d(x)^2 = ab - ab(2x/h - 1)^2 = ab(1 - 4(x - h/2)^2/h^2. Hence (1/ab)y(x)^2 + (4/h^2)(x - h/2)^2 = 1 ...equation of an ellipse qed