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From: Richard Ashbery <basura@invalid.addr.uk>
Newsgroups: comp.sys.acorn.programmer
Subject: Re: Specific numbers but in a random sequence
Date: Sun, 23 Jun 2019 14:01:44 +0100
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In article <20190623120736.3390b842@ian-460-p050na>,
   Ian <Ian.Hamilton@AAUG.net> wrote:
> On Sun, 23 Jun 2019 11:17:26 +0100
> Richard Ashbery <basura@invalid.addr.uk> wrote:

[snip]

> > > DIM array%(18)
> > > array%() = 3,4,5,6,8,9,10,12,15,18,20,24,30,36,45,60,90,120
> > > y = RND(-TIME)
> > > FOR loop = 1 TO 5
> > > FOR I% = 0 TO 18
> > > PRINT array%(RND(18))
> > > NEXT I%
> > > NEXT loop  
> > 
>> There's only one problem which makes no
> > sense to me in that 3 never appears but 0 does.


> The array%() is being initialised from (0) to (17). (18) would contain
> the zero. (0) contains the three.

> Random numbers are 1 to 18. So three doesn't appear, zero does.

> Add '0,' so that array%()=0,3,4,5,6,8 etc. and it should work. 

I have and I've now got my 3 back - excellent. Nice explanation. I
haven't used arrays much so knowledge is lacking.

Richard