X-FeedAbuse: http://nntpfeed.proxad.net/abuse.pl feeded by 78.192.65.63 Path: csiph.com!usenet.pasdenom.info!dedibox.gegeweb.org!gegeweb.eu!nntpfeed.proxad.net!news.muarf.org!news.ecp.fr!feeder1.cambriumusenet.nl!feed.tweaknews.nl!194.109.133.87.MISMATCH!newsfeed.xs4all.nl!newsfeed1.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.000 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'value,': 0.04; 'subject:help': 0.08; 'constructor': 0.09; 'item,': 0.09; 'iterate': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'spaces': 0.09; 'subject:string': 0.09; 'def': 0.12; '","': 0.16; 'boolean': 0.16; 'format:': 0.16; 'received:80.91.229.3': 0.16; 'received:dip0.t-ipconnect.de': 0.16; 'received:plane.gmane.org': 0.16; 'received:t-ipconnect.de': 0.16; 'separated': 0.16; 'sweet.': 0.16; 'values?': 0.16; 'wrote:': 0.18; '(where': 0.19; '>>>': 0.22; 'header:User-Agent:1': 0.23; 'string,': 0.24; 'header:X-Complaints-To:1': 0.27; 'tim': 0.29; "i'm": 0.30; "skip:' 10": 0.31; 'fixing': 0.31; 'go.': 0.31; 'keys': 0.31; 'strip': 0.31; 'option': 0.32; 'subject:from': 0.34; 'subject:with': 0.35; 'skip:s 30': 0.35; 'something': 0.35; 'there': 0.35; 'hi,': 0.36; 'example,': 0.37; 'skip:[ 10': 0.38; 'to:addr:python-list': 0.38; 'sure': 0.39; 'to:addr:python.org': 0.39; 'received:org': 0.40; 'how': 0.40; 'more': 0.64; 'occur': 0.65; 'dict()': 0.84 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Peter Otten <__peter__@web.de> Subject: Re: help with creating dict from string Date: Thu, 06 Nov 2014 18:40:44 +0100 Organization: None References: Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: 7Bit X-Gmane-NNTP-Posting-Host: p57bd941a.dip0.t-ipconnect.de User-Agent: KNode/4.13.3 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 39 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1415295657 news.xs4all.nl 2840 [2001:888:2000:d::a6]:57371 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:80340 Tim wrote: > hi, I have strings coming in with this format: > > '[one=two, three=four five, six, seven=eight]' > > and I want to create from that string, this dictionary: > {'one':'two', 'three':'four five', 'six':True, 'seven':'eight'} > > These are option strings, with each key-value pair separated by commas. > Where there is a value, the key-value pair is separated by '='. > > This is how I started (where s is the string): > s = s.replace('[','').replace(']','') > s = [x.split('=') for x in s.split(',')] > > [['one', 'two'], [' three', 'four five'], [' six'], [' seven', > [['eight']] > > I know I can iterate and strip each item, fixing single-element keys as I > go. > > I just wondered if I'm missing something more elegant. If it wasn't for > the leading spaces and the boolean key, the dict() constructor would have > been sweet. Not everything has to be a one-liner ;) If it works I don't think something >>> s = '[one=two, three=four five, six, seven=eight]' >>> def fix(pair): ... key, eq, value = pair.partition("=") ... return key.strip(), value if eq else True ... >>> dict(fix(t) for t in s.strip("[]").split(",")) {'three': 'four five', 'seven': 'eight', 'one': 'two', 'six': True} is particularly inelegant. Are you sure that your grammar is not more complex than your example, e. g. that "," cannot occur in the values?