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From: Dennis Lee Bieber <wlfraed@ix.netcom.com>
Subject: Re: I am out of trial and error again Lists
Date: Sat, 25 Oct 2014 14:37:11 -0400
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On Fri, 24 Oct 2014 14:15:13 -0400, Seymore4Head
<Seymore4Head@Hotmail.invalid> declaimed the following:


>
>I do understand that.  7 is a number and "7" is a string.
>What my question was...and still is...is why
>Python 3 fails when I try using
>y=1 800 get charter
>
>y in range str(range(10))


	Really... Did you try at an interpreter prompt?

Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

C:\Users\Wulfraed\Documents>python3
ActivePython 3.3.2.0 (ActiveState Software Inc.) based on
Python 3.3.2 (default, Sep 16 2013, 23:11:39) [MSC v.1600 64 bit (AMD64)]
on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> y=1 800 get charter
  File "<stdin>", line 1
    y=1 800 get charter
          ^
SyntaxError: invalid syntax
>>> y = "1 800 get charter"
>>>
>>> y in range str(range(10))
  File "<stdin>", line 1
    y in range str(range(10))
                 ^
SyntaxError: invalid syntax
>>>


>should work because y is a string and str(range(10)) should be

	Yes... BUT:

>>> y in str(range(10))
False
>>> str(range(10))
'range(0, 10)'
>>> "1 800 get charter" in "range(0, 10)"
False
>>>

>>> "1 800 get charter" in "call 1 800 get charter now to get robbed"
True
>>> y in "call 1 800 get charter now to get robbed"
True
>>>



>"y" in str(1) fails.
>It doesn't give an error it's just not True when y is a number.
>

	"y" is not a number, and neither is what you have on the right side.
You are asking if a string appears somewhere inside another string.

-- 
	Wulfraed                 Dennis Lee Bieber         AF6VN
    wlfraed@ix.netcom.com    HTTP://wlfraed.home.netcom.com/