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From: Ian Kelly <ian.g.kelly@gmail.com>
Date: Sat, 25 Oct 2014 08:17:06 -0600
Subject: Re: I am out of trial and error again Lists
To: Python <python-list@python.org>
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On Sat, Oct 25, 2014 at 12:46 AM, Larry Hudson
<orgnut@yahoo.com.dmarc.invalid> wrote:
>> name="123-xyz-abc"
>> for x in name:
>>      if x in range(10):
>
> x is a character (a one-element string).  range(10) is a list of ints.  A
> string will never match an int.  BTW, as it is used here, range(10) is for
> Py2, for Py3 it needs to be list(range(10)).

The last comment is incorrect. You can do membership tests on a Python
3 range object:

>>> range(2, 4)
range(2, 4)
>>> for i in range(5):
...   print(i, i in range(2, 4))
...
0 False
1 False
2 True
3 True
4 False

You can also index them:
>>> range(50, 100)[37]
87

slice them:
>>> range(0, 100, 2)[:25]
range(0, 50, 2)

get their length:
>>> len(range(25, 75))
50

search them:
>>> range(25, 75).index(45)
20

and generally do most operations that you would expect to be able to
do with an immutable sequence type, with the exceptions of
concatenation and multiplication. And as I observed elsewhere in the
thread, such operations are often more efficient on range objects than
by constructing and operating on the equivalent lists.