Path: csiph.com!usenet.pasdenom.info!dedibox.gegeweb.org!gegeweb.eu!nntpfeed.proxad.net!proxad.net!feeder1-2.proxad.net!usenet-fr.net!nerim.net!novso.com!newsfeed.xs4all.nl!newsfeed1a.news.xs4all.nl!xs4all!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.001 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'output': 0.05; 'item.': 0.09; 'parameter': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'subject:How': 0.10; 'cmp=': 0.16; 'received:80.91.229.3': 0.16; 'received:dip0.t-ipconnect.de': 0.16; 'received:plane.gmane.org': 0.16; 'received:t-ipconnect.de': 0.16; 'sorted()': 0.16; 'subject:show': 0.16; 'tuple': 0.16; 'wrote:': 0.18; 'header:User-Agent:1': 0.23; 'simpler': 0.24; 'sort': 0.25; 'header:X-Complaints-To:1': 0.27; '???': 0.30; 'skip:m 30': 0.32; 'quite': 0.32; 'maybe': 0.34; 'skip:d 20': 0.34; "can't": 0.35; 'something': 0.35; 'there': 0.35; 'subject:data': 0.36; 'subject:?': 0.36; 'e.g.': 0.38; 'needed': 0.38; 'to:addr:python-list': 0.38; 'to:addr:python.org': 0.39; 'skip:p 20': 0.39; 'received:org': 0.40; 'even': 0.60; 'skip:u 10': 0.60; 'skip:n 10': 0.64 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Peter Otten <__peter__@web.de> Subject: Re: How to show a dictionary sorted on a value within its data? Date: Wed, 01 Oct 2014 12:24:46 +0200 Organization: None References: Mime-Version: 1.0 Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: 7Bit X-Gmane-NNTP-Posting-Host: p57bd8fb6.dip0.t-ipconnect.de User-Agent: KNode/4.13.3 X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 44 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1412159108 news.xs4all.nl 2850 [2001:888:2000:d::a6]:54646 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:78534 cl@isbd.net wrote: > I have a dictionary as follows:- > > { > u'StarterAmps1': Row(id=4, ain=u'AIN3', name=u'StarterAmps1', > conv=6834.374834509803, Description=u'Starter Amps'), u'LeisureVolts': > Row(id=1, ain=u'AIN0', name=u'LeisureVolts', conv=29.01374215995874, > Description=u'Leisure Volts'), u'RudderPos': Row(id=6, ain=u'AIN5', > name=u'RudderPos', conv=0.028125, Description=u'Rudder Position'), u'xx': > Row(id=7, ain=u'AIN6', name=u'xx', conv=0.028125, Description=u''), > u'LeisureAmps1': Row(id=3, ain=u'AIN2', name=u'LeisureAmps1', > conv=32.727273081945, Description=u'Leisure Amps'), u'StarterVolts': > Row(id=2, ain=u'AIN1', name=u'StarterVolts', conv=28.94469628911757, > Description=u'Starter Volts') } > > I want to output a menu to a user comprising some parts of the > dictionary (ain and Description) sorted by ain. > > Is there some incantation of sorted() that will do what I want? I > can't quite fathom out the 'key=' parameter needed to sort it by the > tuple item. Maybe I need a cmp= ? > > E.g. I want to do something like:- > > for meas in sorted(adc.cfg, key=???): > print(adc.cfg[meas].ain, adc.cfg[meas].Description) > > What's needed in the ??? for meas in sorted(adc.cfg, key=lambda key: adc.cfg[key].ain): print(adc.cfg[meas].ain, adc.cfg[meas].Description) or simpler for row in sorted(adc.cfg.values(), key=operator.attrgetter("ain")) print(row.ain, row.Description) or even for row in sorted( map(operator.attrgetter("ain", "Description"), adc.cfg.values())): print(*row)