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From: Sandman <mr@sandman.net>
Newsgroups: comp.lang.php
Subject: Re: preg_match() oddities and question
Date: Wed, 23 Nov 2011 09:55:22 +0100
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In article <3004614.SPkdTlGXAF@PointedEars.de>,
 Thomas 'PointedEars' Lahn <PointedEars@web.de> wrote:

> >> > So I have this regexp:
> >> > 
> >> > if (preg_match("/^(.*?)\s*(\d*?)\s*([A-Z,a-z,-]*?)$/", $search, $m)){
> >> >     $streetname = uc_words($m[1]);
> >> >     $streetnumber = trim($m[2]);
> >> >     $streetletter = strtoupper($m[3]);
> >> >     $search = trim($streetname . SPACE . $streetnumber .
> >> > $streetletter);
> >> > }
> >> > 
> >> > The desired result is taki9ng the input ($search) and split it into
> >> > its parts as an address, right? $search can be, for example, "foo
> >> > street 34", "longstreet 45b", "longstreet 45 b" or just "longstreet".
> >> 
> >> "10 East 42nd Street, New York, NY 10017, USA".
> > 
> > That wouldn't be a normal swedish address, no. :)
> 
> You had not limited the country or the language of your street addresses.

Well, to my defense, the subject line was "preg_match() and swedish 
characters" until I changed it. I hadn't changed it when I wrote my 
examples.

> My point is that parsing a street name and a house number from a street 
> address is a hard problem that cannot be solved only by applying one regular 
> expression.

Right, but your example is not a valid argument for that conclusion. 
My examples contained the variations of addresses that I wanted to 
match. Or are you saying that there is no way to use regular 
expressions to catch the examples I gave? Because I have a hard time 
believing that.



-- 
Sandman[.net]