Path: csiph.com!usenet.pasdenom.info!aioe.org!news.stack.nl!newsfeed.xs4all.nl!newsfeed4.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Date: Sun, 20 Oct 2013 21:50:07 +0200 From: Luuk User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:24.0) Gecko/20100101 Thunderbird/24.0.1 MIME-Version: 1.0 Newsgroups: comp.lang.php Subject: Re: how to change character to % character? References: <52642C52.9010400@arnowelzel.de> In-Reply-To: <52642C52.9010400@arnowelzel.de> Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit Message-ID: Lines: 20 NNTP-Posting-Host: 2001:980:9089:1:e8e2:d217:7ba6:9128 X-Trace: 1382298612 news.xs4all.nl 15948 [2001:980:9089:1:e8e2:d217:7ba6:9128]:44102 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.php:11502 On 20-10-2013 21:17, Arno Welzel wrote: > richard, 2013-10-20 18:27: > >> I noticed that whenever a song is clicked on that has an apostrophe in the >> name, an error is now being generated. >> The song still plays and the name is reported correctly. >> >> So how can I detect any and all 's within a string and convert them to the >> %27 version? >> >> I had a look at preg-match and don't think that will help. > > See . > > or one of these: http://php.net/manual/en/pdo.prepared-statements.php http://php.net/manual/en/mysqli.quickstart.prepared-statements.php