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From: Arno Welzel <usenet@arnowelzel.de>
Newsgroups: comp.lang.php
Subject: Re: Implied cast differs from explicit cast
Date: Thu, 19 Jan 2012 13:39:07 +0100
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Arno Welzel, 2012-01-19 13:36:

> Jerry Stuckle, 2012-01-17 14:16:
> 
>> On 1/17/2012 12:59 AM, Arno Welzel wrote:
>>> Jerry Stuckle, 2012-01-16 14:45:
>>>
>>>> On 1/16/2012 8:28 AM, The Natural Philosopher wrote:
>>>>> lb wrote:
>>>>>> jstucklex@attglobal.net wrote:
>>>>>>> ...
>>>>>>> No, it is not. '0x12' is a hex number, not an integer. (int)'0x12'
>>>>>>> converts this correctly to 0.
>>>>>
>>>>> Looks like Jerry doesn't know what an integer is either.
>>>>>
>>>>> A hex number of course *is* an integer, unless its a hex representation
>>>>> of floating point.
>>>>>
>>>>> Killfile the prat like I have.
>>>>>
>>>>>
>>>>
>>>> 0x12 is not an integer.  It is a hexadecimal value.
>>>
>>> No, 0x12 (and *not* "0x12") is the hexadecimal *representation* of the
>>> value 18. There is no thing like "hexadecimal value" and "0x12" is a
>>> *string* and not a number at all.
>>>
>>
>> No, it is a hexadecimal value.  It may be an integer, it may be a
>> character, it may be a set of flags... It does not have to be an integer.
>>
>>> In fact PHP only knows to types of numbers: integers and floating point.
>>> There is no "hexadecimal" data type.
>>>
>>
>> Excuse me - there is.  See hexdec().
> 
> <http://php.net/manual/en/function.hexdec.php>
> 
> You don't know what a data type is? Do you?
> 
> See <http://www.php.net/manual/en/language.types.php> and show me, where
> the "hexadecimal data type" is explained.

And you should read the section about *integer* literal in
<http://www.php.net/manual/en/language.types.integer.php> very carefully.

There is no thing as "conversion of hexadecimal values to an integer".

EOD for me.


-- 
Arno Welzel
http://arnowelzel.de
http://de-rec-fahrrad.de