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From: Arno Welzel <usenet@arnowelzel.de>
Newsgroups: comp.lang.php
Subject: Re: Implied cast differs from explicit cast
Date: Tue, 17 Jan 2012 07:00:09 +0100
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Arno Welzel, 2012-01-17 06:59:

> Jerry Stuckle, 2012-01-16 14:45:
> 
>> On 1/16/2012 8:28 AM, The Natural Philosopher wrote:
>>> lb wrote:
>>>> jstucklex@attglobal.net wrote:
>>>>> ...
>>>>> No, it is not. '0x12' is a hex number, not an integer. (int)'0x12'
>>>>> converts this correctly to 0.
>>>
>>> Looks like Jerry doesn't know what an integer is either.
>>>
>>> A hex number of course *is* an integer, unless its a hex representation
>>> of floating point.
>>>
>>> Killfile the prat like I have.
>>>
>>>
>>
>> 0x12 is not an integer.  It is a hexadecimal value.
> 
> No, 0x12 (and *not* "0x12") is the hexadecimal *representation* of the
> value 18. There is no thing like "hexadecimal value" and "0x12" is a
> *string* and not a number at all.
> 
> In fact PHP only knows to types of numbers: integers and floating point.
> There is no "hexadecimal" data type.
> 
>> It can have the same bit pattern as an integer - but it can also have
>> the same bit pattern as a character (Ctrl-R, to be exact).
> 
> Which also applies to the value 18 - this can also be the value of a
> character.
> 
> Example:
> 
> <?php
> $a = 0x12;
> 
> print $a;
> ?>
> 
> Result:
> 
> Value of $a: 18, type of $a: integer

Sorry - the example was not complete:

<?php
$a = 0x12;

$a = intval($a, 16);

print 'Value of $a: ' . $a . ', type of $a: ' . gettype($a);
?>



-- 
Arno Welzel
http://arnowelzel.de
http://de-rec-fahrrad.de